problem26_34

# problem26_34 - 608 A 10 25 . 1 V 52 . 1 A 10 25 . 1 2 1 3 3...

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26.34: a) When the wires are shorted, the full-scale deflection current is obtained: ( 29 ( 29 . 543 0 . 65 A 10 50 . 2 V 52 . 1 3 = + × = = - R R IR ε total b) If the resistance . mA 88 . 1 543 0 . 65 V 52 . 1 : 200 = + + = = = x total x R R V I R c) . 608 V 52 . 1 543 0 . 65 V 52 . 1 - = + + = = x x x total x I R R R ε I So: . 1824 608 A 10 25 . 6 V 52 . 1 A 10 25 . 6 4 1 4 4 = - × = × = = - - x fsd x R I I . 608
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Unformatted text preview: 608 A 10 25 . 1 V 52 . 1 A 10 25 . 1 2 1 3 3 Ω = Ω-× = ⇒ × = =--x fsd x R I I . 203 608 A 10 875 . 1 V 52 . 1 A 10 875 . 1 4 3 3 3 Ω = Ω-× = ⇒ × = =--x fsd x R I I...
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## This homework help was uploaded on 04/19/2008 for the course PHYS 4 taught by Professor Stuart during the Spring '08 term at UCSB.

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