problem26_40

problem26_40 - time constant is s 74 1 s 870 2 2 = = C R

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26.40 : a) Originally, s. 870 . 0 = = RC τ The combined capacitance of the two identical capacitors in series is given by 2 ; 2 1 1 1 tot tot C C C C C C = = + = The new time constant is thus . s 435 . 0 ) ( 2 s 870 . 0 2 = = C R b) With the two capacitors in parallel the new total capacitane is simply 2 C. Thus the
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Unformatted text preview: time constant is . s 74 . 1 ) s 870 . ( 2 ) 2 ( = = C R...
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