problem26_44

problem26_44 - ( 2 2 2 P V R R V P c) . c 45 kW) (4.1 ) hr...

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26.44: a) . A 1 . 17 V 240 W 4100 = = = V P I So we need at lest 14-gauge wire (good up to 18 A). 12 gauge is ok (good up to 25 A). b) = = = = 14 W 4100 ) V 240
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Unformatted text preview: ( 2 2 2 P V R R V P c) . c 45 kW) (4.1 ) hr 1 ( /kWhr) c (11 cost hour, 1 in /kWhr c 11 At / = / = /...
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This homework help was uploaded on 04/19/2008 for the course PHYS 4 taught by Professor Stuart during the Spring '08 term at UCSB.

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