problem26_52

problem26_52 - 26.52: a)The equivalent resistance of the...

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Unformatted text preview: 26.52: a)The equivalent resistance of the two bulbs is 1.0 . So the current is: I= V 8.0 V = = 4.4 A the current through each bulb is 2.2 A. Rtotal 1.0 + 0.80 Vbulb = - Ir = 8.0 V - (4.4 A) (0.80 ) = 4.4 V Pbulb = IV = (2.2 A) (4.4 V) = 9.9 W b) If one bulb burns out, then I= V 8.0 V = = 2.9 A P = I 2 R = (2.9 A) 2 (2.0 ) = 16.3 W, Rtotal 2.0 + 0.80 so the remaining bulb is brighter than before. ...
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This homework help was uploaded on 04/19/2008 for the course PHYS 4 taught by Professor Stuart during the Spring '08 term at UCSB.

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