problem26_72

problem26_72 - . 002 . 3 2 1 =-- R R R From (i) and (ii) ....

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26.72: The current for full-scale deflection is 0.02 A. From the circuit we can derive three equations: (i) A) 02 . 0 ( 0 . 48 ) A 02 . 0 A 100 . 0 )( ( 3 2 1 = - + + R R R . 0 . 12 3 2 1 = + + R R R (ii) A) 02 . 0 )( (48.0 A) 0.02 A 00 . 1 )( ( 3 2 1 R R R + = - + . 980 . 0 0204 . 0 3 2 1 = - + R R R (iii) A) 02 . 0 )( (48.0 A) 0.02 A 0 . 10 ( 3 2 1 R R R + + = - . 096 . 0 002
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Unformatted text preview: . 002 . 3 2 1 =-- R R R From (i) and (ii) . 8 . 10 3 = R From (ii) and (iii) . 12 . so And . 08 . 1 1 2 = = R R...
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This homework help was uploaded on 04/19/2008 for the course PHYS 4 taught by Professor Stuart during the Spring '08 term at UCSB.

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