problem26_78

problem26_78 - )( A 6 . 3 ( 1 1 Ω = ⇒ = Ω R R μ And...

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26.78: In order for the second galvanometer to give the same full-scale deflection and to have the same resistance as the first, we need two additional resistances as shown below. So: . m 4 . 91 ) mA 496 . 1 ( ) 0 . 38
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Unformatted text preview: )( A 6 . 3 ( 1 1 Ω = ⇒ = Ω R R μ And for the total resistance to be 65 : Ω . 9 . 64 0914 . 1 . 38 1 65 2 1 2 Ω = ⇒ Ω + Ω + =-R R...
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This homework help was uploaded on 04/19/2008 for the course PHYS 4 taught by Professor Stuart during the Spring '08 term at UCSB.

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