This preview shows page 1. Sign up to view the full content.
Unformatted text preview: A, 300 . 1 = I A, 500 . 2 = I A, 200 . 3 = I just as in part (a). f) Changing the 57V battery for an 80V battery just affects the calculation in part (c). It changes to: Left loop: . 210 140 2 1 = + I I Right loop: . 210 35 80 2 3 =I I Currents: . 3 2 1 = +I I I Solving for the three currents: , A 403 . 1= I A, 269 . 2 = I A. 672 . 3 = I So the total current for the full circuit is the sum of (b), (d) and (f) above: A, 184 . 1 = I A, 576 . 2 = I A. 392 . 3 = I...
View
Full
Document
 Spring '08
 Stuart
 Current

Click to edit the document details