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ISM_chapter5_part2

# ISM_chapter5_part2 - Chapter 5 Chemical Reactions 205 79...

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Chapter 5: Chemical Reactions 205 79 . Answer: 121 mL HNO 3 Strategy and Explanation: Given the mass of one reactant, the balanced chemical equation for a reaction, and the molarity of a solution containing the other reactant, determine the volume of the second solution for a complete reaction. The stoichiometry of a balanced chemical equation dictates how the moles of reactants combine, so we will commonly look for ways to calculate moles. Here, the mass and molar mass can be used to find the moles of one reactant. Then we will use the equation stoichiometry to find out moles of the other reactant needed. Then we will use the moles and molarity to find volume in liters and convert liters into milliliters. Notice: It is NOT appropriate to use the dilution equation when working with reactions! We learn from the balanced equation that 1 mol of Ba(OH) 2 reacts with 2 mol HNO 3 . 1.30 g Ba(OH) 2 " 1 mol Ba(OH) 2 171.3416 g Ba(OH) 2 " 2mol HNO 3 1mol Ba(OH) 2 " 1 L HNO 3 solution 0.125 mol HNO 3 " 1000 mL 1 L = 121 mL HNO 3 solution 80. Answer: 204 mL H 2 SO 4 Strategy and Explanation: Given the mass of one reactant, the balanced chemical equation for a reaction, and the molarity of a solution containing the other reactant, determine the volume of the second solution for a complete reaction. The stoichiometry of a balanced chemical equation dictates how the moles of reactants combine, so we will commonly look for ways to calculate moles. Here, the mass and molar mass can be used to find the moles of one reactant. Then we will use the equation stoichiometry to find out moles of the other reactant needed. Then we will use the moles and molarity to find volume in liters and convert liters into milliliters. Notice: It is NOT appropriate to use the dilution equation when working with reactions! We learn from the balanced equation that 2 mol of NaBH 4 reacts with 1 mol H 2 SO 4 . 1.35 g NaBH 4 " 1 mol NaBH 4 37.832 g NaBH 4 " 1 mol H 2 SO 4 2 mol NaBH 4 " 1 L H 2 SO 4 solution 0.0875 mol H 2 SO 4 " 1000 mL 1 L = 204 mL H 2 SO 4 solution 81 . Answer: 22.9 mL NaOH solution Strategy and Explanation: Given the volume and molarity of a solution containing one reactant, and the molarity of a solution containing the other reactant, determine the volume of the second solution for a complete reaction. First, determine what chemical reaction occurs between the reactants, write the appropriate products, and balance the equation. Then use the volume and molarity to find the moles of one reactant. Then use the equation stoichiometry to find out moles of the other reactant needed. Then use the moles and molarity to find volume in liters, and convert liters into milliliters. Notice: It is NOT appropriate to use the dilution equation when working with reactions!

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ISM_chapter5_part2 - Chapter 5 Chemical Reactions 205 79...

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