ISM_chapter7_part2

ISM_chapter7_part2 - Chapter 7: Electron Configurations and...

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Unformatted text preview: Chapter 7: Electron Configurations and the Periodic Table 315 25 Mn 3+ electron configuration: 1s 2 2s 2 2p 6 3s 2 3p 6 3d 4 . Mn 3+ has 4 unpaired electrons : 3d [Ar] 77. Answer/Explanation: When transition metals form cations, the electrons lost first are those from their valence (highest n) s orbitals. 24 Cr electron configuration: 1s 2 2s 2 2p 6 3s 2 3p 6 3d 5 4s 1 . Cr has 6 unpaired electrons : 3d 4s [Ar] 24 Cr 2+ electron configuration: 1s 2 2s 2 2p 6 3s 2 3p 6 3d 4 . Cr 2+ has 4 unpaired electrons : 3d [Ar] 24 Cr 3+ electron configuration: 1s 2 2s 2 2p 6 3s 2 3p 6 3d 3 . Cr 3+ has 3 unpaired electrons : 3d [Ar] 78 . Answer/Explanation: 16 S electron configuration: 1s 2 2s 2 2p 6 3s 2 3p 4 or [Ne]3s 2 3p 4 79. Answer/Explanation: (a) 40 Zr electron configuration: 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s 2 4p 6 4d 2 5s 2 or [Kr]4d 2 5s 2 (b) 45 Rh electron configuration: 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s 2 4p 6 4d 7 5s 2 or [Kr]4d 7 5s 2 80 . Answer/Explanation: (a) 63 Eu electron configuration: [Xe]4f 7 6s 2 or [Xe]4f 6 5d 1 6s 2 (b) 70 Yb electron configuration: [Xe]4f 14 6s 2 or [Xe]4f 13 5d 1 6s 2 Valence Electrons 81. Answer/Explanation: F . . .. .. . In . . . Te . . . . . . Cs . (a) (b) (c) (d) 82 . Answer/Explanation: (a) (b) (c) (d) Sr . . Br . . . . . . . Ga . . . Sb . . . .. 83. Answer/Explanation: (a) 11 Na + electron configuration: 1s 2 2s 2 2p 6 or [Ne] (b) 13 Al 3+ electron configuration: 1s 2 2s 2 2p 6 or [Ne] (c) 17 Cl – electron configuration: 1s 2 2s 2 2p 6 3s 2 3p 6 or [Ar] 11 Na + and 13 Al 3+ are isoelectronic. They have the same number of electrons. 84 . Answer/Explanation: (a) 20 Ca 2+ electron configuration: 1s 2 2s 2 2p 6 3s 2 3p 6 or [Ar] (b) 19 K + electron configuration: 1s 2 2s 2 2p 6 3s 2 3p 6 or [Ar] (c) 8 O 2– electron configuration: 1s 2 2s 2 2p 6 or [Ne] 20 Ca 2+ and 19 K + are isoelectronic. They have the same number of electrons. 85. Answer/Explanation: 35 Br electron configuration: 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s 2 4p 5 35 Br – electron configuration: 1s 2 2s 2 2p 6 3s 2 3p 6 3d 10 4s 2 4p 6 86 . Answer/Explanation: 50 Sn electron configuration: [Kr]4d 10 5s 2 5p 2 50 Sn 2+ electron configuration: [Kr]4d 10 5s 2 50 Sn 4+ electron configuration: [Kr]4d 10 Chapter 7: Electron Configurations and the Periodic Table 316 Paramagnetism and Unpaired Electrons 87. Answer/Explanation: (a) Diamagnetic elements have completely filled subshells. While the subshell is incompletely full, Hund’s Rule requires that the electrons be as unpaired as possible. Therefore, only the element with completely filled subshells will be diamagnetic. The only period four transition element with completely filled s and d subshell is Zn ([Ar]3d 10 4s 2 )....
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This note was uploaded on 04/20/2008 for the course CHE 131 taught by Professor Kerber during the Spring '08 term at SUNY Stony Brook.

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ISM_chapter7_part2 - Chapter 7: Electron Configurations and...

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