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Day 3

Day 3 - Kinematics"Problems You'll recall that we've...

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Kinematics “Problems” You’ll recall that we’ve derived three equations of kinmatics for constant acceleration: v f = v 0 + at, x f = x 0 + v 0 t + 1 2 at 2 , v 2 f = v 2 0 + 2 a ( x f - x 0 ) Because these are vector equations, each one is actually three equations , one for ˆ x , one for ˆ y , and one for ˆ z . To help remember this, even when we do a one-dimensional problem, I’m going to ask that you use vector notation. Constant acceleration problems, because you’ve already done the calculus, are just algebra problems . The trick is to figure out what’s being asked for.

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Kinematics: Discrete vs. Continuous Experimentalists can only measure position at discrete points. That is, they make a table of where an object is when: Time (sec) Position (m) 0 ± 0 . 1 0 ± 0 . x 1 ± 0 . 1 0 . 9 ± 0 . x 2 ± 0 . 1 4 . 3 ± 0 . x 3 ± 0 . 1 8 . 8 ± 0 . x 4 ± 0 . 1 16 . 4 ± 0 . x So what do you think we can do with this?
Average vs. Instantaneous Experimentalists can’t measure an instantaneous velocity, only an average velocity and acceleration v = x t , a = v t .

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Day 3 - Kinematics"Problems You'll recall that we've...

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