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Practice Test 1

# Practice Test 1 - EE 4343 Test 1 Spring 2002 Definitions...

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R base_p 23.04 = R base_s 120 volt I rat_s := R base_s 1.44 = R wp 0.01 R base_p := R wp 0.23 = R ws 0.01 R base_s := R ws 0.014 = Problem 3: A three-phase load is drawing 250 kW real power at a power factor of 0.75 lagging. a) Find the apparent power S drawn by the load in kVA 333.3 . b) Find the reactive power Q drawn by the load in kVAR 220.5 . c) Find the capacitor bank rating in kVAR to increase the combined power factor to unity (1.0) 220.5 . SV I = PV I pf = QV I sin acos pf () = SP 2 Q 2 + = acos 0.75 ( ) 41.41 deg = S P pf = S 250 kW 0.75 := S 333.3 kVA = Q S sin acos 0.75 := Q 220.5 kVAR = EE 4343, Test 1, Spring 2002: Dr. M. Giesselmann, February 13, 2002 Definitions: freq 60 Hz := ω 2 π freq := MW 1000 kW kVA kW kVAR kW m 1000 MVA 1000 kW MVAR 1000 kW Problem 1: a) What is the principal advantage of AC power systems compared to DC power systems? The ability to step voltages up and down for long distance transmission. b) Give two solutions to eliminate oscillations of the instantaneous power in AC power systems.

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• Spring '08
• GIESSELMANN
• Electric power transmission, Electricity distribution, Three-phase electric power, Hz kVAR kW, 60 Hz = Vrms50 50 Hz N A

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Practice Test 1 - EE 4343 Test 1 Spring 2002 Definitions...

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