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Example 2.3

# Example 2.3 - Example 2.3 Dr Michael Giesselmann A...

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θ new acos 0.95 ( ) := θ new 18.19 deg = Q new P tan acos 0.95 ( ) ( ) := Q new 32.87 kVAR = S new P 2 Q new 2 + := S new 105.26 kVA = Q C Q Q new := Q C 42.13 kVAR = zero 1 watt := k 0 1 .. := P d zero P := Q l P P j Q + := Q c P P j Q + j Q C := S old zero S e j 36.87 deg := S new zero S new e j 18.19 deg := Additional assumption to calaculate Capacitor Size (not in the textbook) V LL 480 volt := Q C V LL 2 X C = V LL 2 ω C = X C 1 ω C = C Q C V LL 2 ω := C 485.059 µ F = Example 2.3: Dr. Michael Giesselmann, January 23, 2008 A single-phase source delivers 100 kW to a load operating at a power factor of 0.8 lagging. Calculate the reactive power to be delivered by a capacitor connected in parallel with the load in order to raise the source power factor to 0.95 lagging. Also draw the power triangle for the source and load. Assume that the source voltage is constant and neglect the line impedance between the source and the load.

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