I
c
45.279 amp
=
arg I
c
()
34.3deg
=
I
a
I
b
+
I
c
+
9.536
4.254j
+
amp
=
Now using Symmetrical Components:
V
p
Z
p
I
p
⋅
=
using
V
p
A
V
s
⋅
=
V
s
A
1
−
V
p
⋅
=
I
p
A
I
s
⋅
=
I
s
A
1
−
I
p
⋅
=
we get
A
V
s
⋅
Z
p
A
⋅
I
s
⋅
=
multiplying with A
1
we get:
A
1
−
A
⋅
V
s
⋅
A
1
−
Z
p
⋅
A
⋅
I
s
⋅
=
which simplifies to:
V
s
A
1
−
Z
p
⋅
A
⋅
I
s
⋅
=
V
s
Z
s
I
s
⋅
=
with
Z
s
A
1
−
Z
p
⋅
A
⋅
=
1
3
1
1
1
1
e
j
2
π
⋅
3
⋅
e
j
4
π
⋅
3
⋅
1
e
j
4
π
⋅
3
⋅
e
j
2
π
⋅
3
⋅
⋅
Z
ph
Z
n
+
Z
n
Z
n
Z
n
Z
ph
Z
n
+
Z
n
Z
n
Z
n
Z
ph
Z
n
+
⋅
1
1
1
1
e
j
4
π
⋅
3
⋅
e
j
2
π
⋅
3
⋅
1
e
j
2
π
⋅
3
⋅
e
j
4
π
⋅
3
⋅
⋅
yields
Z
ph
3Z
n
⋅
+
0
0
0
Z
ph
0
0
0
Z
ph
V
s
Z
ph
n
⋅
+
0
0
0
Z
ph
0
0
0
Z
ph
I
s
⋅
=
V
0
V
1
V
2
Z
ph
n
⋅
+
0
0
0
Z
ph
0
0
0
Z
ph
I
0
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 Spring '08
 GIESSELMANN
 Impedance, Volt, Harshad number, Symmetrical components, arg

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