# dd assignment 1 - SSIGNMENT NO.1 DIGITAL DESIGN What is the...

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SSIGNMENT NO.1 DIGITAL DESIGN A Q No.2.16: What is the hexadecimal equivalent of 12648430? SO (12648430) 10 = ( 110 000 001 111 111 111 101 110 ) 2 6 0 1 7 7 7 5 6 SO (12648430) 10 = (60177756) 8 NOW ( 1100 0000 1111 1111 1110 1110 ) 2 C 0 F F E E SO (12648430) 10 = COFFEE Q No.2.1(d): SOLVE 67.24 8 = ? 2 2 ) 8 100 2 DIVISION Quotient Remainder Coefficient 12648430/2 6324215 0 0 6324215/2 3162107 1 1 3162107/2 1581053 1 1 1581053/2 790526 1 1 790526/2 395263 0 0 395263/2 197631 1 1 197631/2 98815 1 1 98815/2 49407 1 1 49407/2 24703 1 1 24703/2 12351 1 1 12351/2 6175 1 1 6175/2 3087 1 1 3087/2 1543 1 1 1543/2 771 1 1 771/2 385 1 1 385/2 192 1 1 192/2 96 0 0 96/2 48 0 0 48/2 24 0 0 24/2 12 0 0 12/2 6 0 0 6/2 3 0 0 3/2 1 1 1
Q No.2.2(a): SOLVE 1234 8 = ? 2 = ? 16 ) 8 100
SO (1234) 8 = (001010011100) 2 Now ( 0010 1001 1100 ) 2 2 9 C SO (1234) 8 = 29C Q No. 2.6(a): SOLVE 125 10 = ? 2 SOLUTION: (125) 10 = ( ) 2 DIVISION QUOTIENT REMAINDER COEFFICIENT 125/2 104 1 1 104/2 52 0 0 52/2 26 1 1 26/2 13 1 1 13/2 6 1 1 6/2 3 1 1 3/2 1 1 1 SO (125) 10 = (1111101) 2 Q No. 2.6(b): SOLVE 3489 10 =? 8 SO (3489) 10 = (6641) 8 Q No. 1.3: DEFINE THE FOLLOWING ACRONYMS: ASIC,CAD,CD,CO,CPLD,DIP,DVD,FPGA,HDL,IC,IP,LSI,MCM,MSI,NRE,PBX,PCB,PL