RF Circuit Design Test 2

# RF Circuit Design Test 2 - EE 4002-2 Test 1 55N= Fall 2006...

This preview shows pages 1–9. Sign up to view the full content.

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: EE 4002-2 Test # 1 55N= Fall 2006 1. Design a transmission line (TL) length so that the following circuit has a 2/0 purely real input impedance at 950 MHz. Assume vp = 0.69c. What is the / reflection coefﬁcient at the load 11, and at input to the TL Fin? What is the standing wave ratio, and insertion loss (in dB) at the input of the TL? ‘ i 6* ' ac1Jmc= 339"" l K: : Zc: "\$.79 2 2.." Z_JL 4.257,: ‘56.. 2 +0ii.27 27—1?- ZS" zk;o.5‘ r12 a l i??? 2L: awe-13 ’ 4 vm“Wuwwnwwwewwaumymm‘mmmwmme.mmmqmmm-wm [NAME TITLE owe. NO. DATE SMITH CHART FORM ZY—m-N COLOR BY J. COLVlN, UNIVERSITY OF FLORIDA, I199? ‘\ ‘ NORMAUZED EMPEDANCE AND ADM” IANCE COORDINATES 0.12 11.13 0.“ 0.14 M Y mg 0.38 90 0.37 “a a 15 A ‘00 80 0 Qua B ‘ 35 0,6, “1‘- \\° 5 g 3 ; g N >9 7a 034 “\$1 s -. c: 4,? w on .5 2- v * 5 so 43: '1 ‘31 1“" 3 0 95‘ u; \$163“ . 30 ~11: B55 1, \$1 0 02 3- 0e? a“ as“ ob \ .5- 5 Q ﬁe .o 0 A?» 0; Q o w k 06‘ ‘1 7,1 0 <9 ‘* Y‘ 'J W PS J \$9 1 0 4 0 “\$3 \‘9 % \qp‘ 1: in 2-? St, 5- 1 29 é a N 0&5" 0 '5 § 0 a c. . §s§ § %%¢ " [v n“ \ Q! '” é”) e 33 0 v k 6' .I a a g 4‘ T 9 V a 1:, w 5'0 & s a. 5 ‘5 05 1?.” (7' 3" ° ’ 1° '-‘ \$9 35 0 a” 10 g °° Q P i ,9 SF 5 5 90 2; a: w to O E 1 Va g g E: a I" '0 91 o a .5 a 5' 5? an E, n E ° 1: a: b “T -p 3 21; ‘é—Eai ? ” 5" .o —: 1‘s . :1 . «=2 . a; a; 1:. oz . . no. ._ =.. ~. 0' z a a 3 a a c a a a .1. a .- m a a. m ‘- - 27‘ p a z 9- . 1v .— . . :- .== 1: n 8 3 3 e a a 1: 01 O‘Ln'l I r RBISTANCECO ONENT Zo, RCON UCTANCECOMPO (/Yo a 5:51 v n a . 0.2 53' m o .e a 3g. x . gr: '5 1a a ‘ 0 g . 5:. 1:: a? V -a> ‘0 a xi‘.‘ ~0 0 1: an ‘3 3 z “I J}. m . . ' oe- 21'0 1:111 an L2'0 RADIALLYSCALEDPARAMETERS TOWARD LOAD ~> <— TOWARD GENERATOR 1.1 1.2 1.1 1 15 10 1 5 4 3 2 1 (-141RHH'H“L”HA-H.‘1'l.'.‘..'n-1-1-H'x;.lu'1 ‘1‘1‘2 ‘1‘1'r1'v‘1’a'151'r‘1‘ux‘«1’ .1 * 3 2 1 .1 1.2 1.3 .4 Ls 1.3 3 10 20 an ‘ ‘ <9 20 30—0 0.1 0.2 0.1 0.6 0.8 1 1.5 2 :1 1 5 11 10 15» ﬁg? 9 .h—r1..'...'r.1ﬁ Hm. 1‘.'.'.':u'—+—I.u 11w; . . «a 11.01 00 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.81.9 2 2.5 3 1 5 10m ‘7 ﬁg; . 0.1 01 0.99 0.95 0,11 0,8 0.7 0.6 0,5 0.4 0.3 0.2 0.1 0 0° ..,....._._4 ...v_....._.. .4 .1L__._...1..L....._. . CENTER 6" 0 0.1 0,2 0.3 0.1 0.5 0.6 0.7 0.11 0.9 1 1.1 1.2 1.3 1.1 1.5 1.6 1.1 1.3 1.9 2 4‘} i.._4_,..1..1..v_._..x.,1.;;_....,._._J,4....,..4_._.U1..11..HH4“....H.LUL.._,_J_,.....H-_._._,.1H.H_._L_..U ORIGIN 2. In order to increase powergain in a wireless transmitter, we wish to cascade two transistor ampliﬁer circuits. We would like to create DC isolation, maintain wide bandwidth, and of course achieve maximum power transfer. Design a matching network that will accomplish all of these things, at minimal “cost”. (Cost simply means fewest components.) l i A ’0 22;: 2r¥cso ZOUT1=6O~j16 ; /,2_ away. , 7, l Zm=100—j35 "- 2 ’7”? '7 2c: mice 7 in“, § ‘ L—iﬁ? , c: d ‘ l . t FL, an zcca'o) EREWLN jaw?) i)? H I Aka; err F050 / /.(9./.3= 1/2.) ® 3Q.” erFL. WM 0 so I a /’ L: sOCIXL £Mw " aw W‘ # 217\$ A If,» ['0 \ l I N, 601% w lijvé —l~‘ ﬂew], 9’ ‘ ‘ , ,V l, 37— i l ‘ﬂ\ ‘ i . K v? \ l/ a: «0 2 _ 3w ‘ A .1 - j _ I 29/: \ ’ “Wimmwmnmmmwmm , mm. 7 7". n r RAmMJY scams PARAMETERS 0.?» ' ohmz 1,2 I :4 «.65 0:1' 3 galaxy 'ua‘ uz 1 0.4 3 0.5 '01s 10 20 :18 L19 0.8 0.1 V 9.9 i Name: Class: Purpose Question: » .. \ \ﬁAéﬁ. a. Am... w 0.. I..m 0.. J I. o 5 2 4 n . I. 3 . é... o n. 4.. M: m 3 A .Z r W 3.. m n. 1 T z. 2 :9, 5.1 1 x... m u 1..6. u w l L:5. . a. 1 u. . H m. M, . D L u m 2 .A . ,x W U mu. 1 m J. L Q I my. lugs : 0.4 H_o.a _ 02‘ a; V n: V0.7 1.7 . .1'6 A 10.3 DJ ()1! > X“? ﬁaéii‘é’a mam wéﬁ’? Qm 5mg £33; ﬁagﬁmﬁ ﬁsiw 3. Create the best possible matching network for a load impedance @ ZL =126—— j39 using a 9M8 TL segment and a stub line with a length of 0.14A. (assume characteristic impedance of 50 Q) 4:— 93/9 -~—-> . 22.59 '1). 0378 @ g k is 3 maﬁa: + 7‘5 a, 0.12; )c/V,,,__,‘f\\ .r o /4 =-.o?§:—J—-— (CSAftrfM o q 3‘ M: T‘— Kx‘ d’ ' dz“. 1“, (50) (D 2mm if agosx M»? ,3 Z _ V‘ ‘ 'l’ f :— 0_Q.‘ ‘OJ °*5:?:.,.,,.\,, “4“” “~" ~ 30?} CZW :4g-JNS— 2. l0 . V... = 4. If the phase velocity of a TL 0.69c, what is the relative permittivity of the dielectric assuming it is nonmagnetic? Upﬁx \$m.:nL~— = £; 2 C Hiram. V67 5. We need a parallel plate TL (assume lossless) with a characteristic C8) impedance of 50 Q. Eindiher/h ratio using a dielectric with 2. = 2.1. What is Seff fffotthisIliw/h ratio? Va}; / 7- / J . Ha ‘ 2 '- 20 g, > 5:7 fr 2. I}; 2 —2I :: :: /‘ 8 ,MWW.WMWWWWWWwe NAME TITLE DWG. NC). DATE SMITH CHART FORM ZY—01 -N COLOR BY J. COLWNl UNIVERSli OF- FLORIDA: 1997 V NORMALIZED iMPEDANCé AND DWOORDINATES ‘ 0 u 0.121 0.1"; D M \ . IE . 0‘ ' 4/0379 M 90 ' 7 0‘35 ’11: \ 70 a m =2 e .3 ‘3 9:. =3 ' T a f a f a, \‘x , o a. V ~; \ ,1 0'9 q.“ :- ” - e go of: \ 1, ’14“ “ ‘9 ~ a «ﬁg ~. ’5“ odd) \ . <9 ’6 '? Q; \ 43\$ ‘ " g6 ,1 a "‘0 x o \$1 1‘ 1 “‘36 a \ (\$9 ‘4 1 a (9 \ 0Y2? . a \ x 4 Q: \ ’0 o x. n 6 la - , a \ B / 0- '5 1 /’ '09 \ ,1 3, we a I x 0 ﬁx \ 0 a :1, , .. o. . <1 ‘34 . z . '° ‘ 9 z“ '2 11/ ,’ .9. \D ’f’ z‘ 0 . 5 a so , “a ‘21 5 ; o E O h F‘ ’0 ’ 0% o . "1 a a , ’ . .,. ’ 0 CI. ‘1 M a \$ 3 i @“Cl 4 . . . . L. w. -. m. . 1 . . =9 . c? w o 2 .— 1; , g a o o a c 4, u .4 \4 er. 4— N ‘0 z n r: g ‘ 5 ' ~ 1» ' 5v .— . . 1 . . n 0 ﬂ 3 +| ’ a as ’ O m 71 RESISTA ECOMPONENT xz ORCONDUCTAN OMPONENT o .1: 3! g - . g 9 ¢ .. a g :57. 0 ~ 2 a: 2 U 41 b In a If: D «a {a ., QR -0 0 3’ 3’ E Q! If?" 06‘ are E. 1 _ ' 1100 RADlALLYSCALEDPARAMETERs TOWARD LOAD —> <— TOWARD GENERATOR , L6 1.4 1.21.11 15 10 7 5 4 3 2 1 A. A. 1 .'—.—'~. ‘1'1‘1' "'1‘1"~1—J~r‘-+.'.‘..'..‘1‘1+H—HJ' 1'1'.'1.'.'.'.—+.J‘.'..‘.+ 4 3 z 1 11 1.1 1.2 1.314 1.6 1.8 2 3 4 5 10 20 10 12 14 20 30.:0 0.1 0.2 0.4 0.6 0.31 1.5 2 3 4 5 5 , ‘5:.’va—+—-¢—-‘.*%"1 NU“ Mani—H: a.:..m1.h—.—1—H1‘1‘.‘+H‘.'1—w—:Lr-l+a—+IrwHM. 1‘» 1 0.9 00 0.7 0.6 0,5 0.4 0.3 0.2 0.1 0.05 0.01 00 1,1 1.2 1.2 1.4 15 1.6 17 LB 1.9 2 2.5 3 4 °‘/ I . 0.11 0.7 0.0 0.5 0.4 0.3 0,2 0.1 01 0.99 0.05 0.9 0.3 0.7 0.5 0.5 04 0. 0.2 0.1 ...,.“HHHHHH..1_L_..1.U...,.._,.1....11H.._.T »..1,1_L_..,. . ._L.....J_1.1., CENTER 0 0.1 0.2 0.3 0.4 0.5 0.0 0.1 0.8 09 1 1.1 1.2 1.3 1.4 15 1.6 1.7 1.8 13 in”....1.....,,1.4_1,...,1“.41.... “HM-Wu..111...1,L1....1_..__1__..11...1,,..1_1_..,1.H, ORIGIN 6. Find the resistance and inductance of a copper wire at 4 GHz. The wire is 15 cm long and has a diameter of 1 mm. JO a. Find the characteristic impedance of a M4 transformer to match a 50 Q microstrip line to a transistor with an input impedance of 13.5 (2. 2AM 5.. 2c .41 b. Find theilléﬁgthandazi/ijthinf this parallel plate M4 transformer. Assume the dielectric we use is nonmagnetic, has thickness of 2 mm, and er = 2.6, and f0 = 900 MHz. ' cl. “” 7 ll c. What would be the beneﬁt of using a material with a higher dielectric constant er? (29)“? a ‘l‘ Ma may: {am 20 : ZGJL % 2 i geld. amicaé’L ‘1) ﬂux climate? frugal/er I Mmmmwm.w.wmwww W hQ/VOLJ. g 2, 8. Find the component values for a Iow—GHz range biasing network for a BJT inverting ampliﬁer shown below. Design for class AB operation. V55: 5V, V35: 0.7 V, B =1QO, [c = 10 mA. Draw the AC equivalent circuit and estimate the small signal gain. ...
View Full Document

• Spring '06
• Scalzo
• Impedance matching, Standing wave ratio, Impedance bridging, Characteristic impedance, chart form, real input impedance

{[ snackBarMessage ]}

### Page1 / 9

RF Circuit Design Test 2 - EE 4002-2 Test 1 55N= Fall 2006...

This preview shows document pages 1 - 9. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online