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f2006Solns6

f2006Solns6 - ECE 190 — Fall 2006 Assignment 6 Solutions...

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Unformatted text preview: ECE 190 — Fall, 2006 Assignment 6 Solutions Section 6.2 • 20 (a) first digit cannot be zero 9 × 10 × 10 × 10 = 9000 (b) first digit cannot be zero and last digit must be odd 9 × 10 × 10 × 5 = 4500 (c) first digit cannot be zero, other digits cannot repeat 9 × 9 × 8 × 7 = 4536 (d) last digit must be odd, first digit cannot be zero or last digit, others must be different 8 × 8 × 7 × 5 = 2240 • 30 (a) The six people can be arranged in 6! = 720 ways. (b) The question is slightly ambiguous as there may be an aisle on one end or on both ends of the six seats. Assuming that there is an aisle only on one end, the doctor can be seated there in one way while the others can be seated in 5! = 120 ways. The total is 120. (c) Consider the three married couples as three units. The units can be arranged in 3! = 6 ways. • 36 (a) See text. (b) There are P (9 , 6) = 60 480 arrangements....
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f2006Solns6 - ECE 190 — Fall 2006 Assignment 6 Solutions...

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