final exam MC review file 2

final exam MC review file 2 - V1 SECTION V STOICHIOMETRY...

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V–1 SECTION V: STOICHIOMETRY INDEX: V001 LEVEL: (U) ANSWER: KEYWORDS: formulas and equations, ALTERNATIVE FORMAT: (SA) Omit responses. When an electric discharge is passed through boron trichloride a new compound is formed. What is its simplest formula if on analysis it is shown to contain 0.0878 g of chlorine and 0.0131 g of boron? Atomic Molar Masses B 10.8 g·mol –1 Cl 35.5 g·mol –1 (A) BCl (B) BCl 2 (C) BCl 3 (D) B 2 Cl 3 INDEX: V002 LEVEL: (U) ANSWER: KEYWORDS: formulas and equations ALTERNATIVE FORMAT: (SA) Omit responses. What is the empirical formula for the substance with this analysis: Elemental Analysis Na 54.0% B 8.50% O 37.5% Atomic Molar Masses B 10.8 g·mol –1 Na 23.0 g·mol –1 O 16.0 g·mol –1 (A) Na 3 BO 3 (C) Na 2 B 2 O 3 (B) Na 4 BO 4 (D) NaB 2 O 2 (SA) = short answer; (FR) = free response; (TF) = true/false (U) = understanding; (A) = analysis; (G) = generalization
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Stoichiometry V–2 INDEX: V003 LEVEL: (U) ANSWER KEYWORDS: formulas and equations ALTERNATIVE FORMAT: (SA) Omit responses. A compound is found to consist of 34.9% sodium, 16.4% boron and 48.6% oxygen. Its simplest formula is Atomic Molar Masses B 10.8 g·mol –1 Na 23.0 g·mol –1 O 16.0 g·mol –1 (A) NaBO 2 (D) Na 3 BO 3 (B) NaBO 3 (E) Na 3 BO 4 (C) Na 2 B 4 O 7 INDEX: V004 LEVEL: (U) ANSWER: KEYWORDS: formulas and equations ALTERNATIVE FORMAT: (SA) Omit responses. When Pb(NO 3 ) 2 is heated in air, it decomposes to a lead oxide. If 2.00 g Pb(NO 3 ) 2 produce 1.35 g of the oxide, what is the formula of the oxide? Atomic Molar Masses N 14. g·mol –1 O 16. g·mol –1 Pb 207. g·mol –1 (A) PbO (B) PbO 2 (C) Pb 2 O 3 (D) Pb 3 O 4 INDEX: V005 LEVEL: (U) ANSWER: KEYWORDS: formulas and equations ALTERNATIVE FORMAT: (SA) Omit responses. If 2.68 g of hydrated sodium sulfate, Na 2 SO 4 . x H 2 O, on heating produces 1.26 g H 2 O, what is the empirical formula of this compound? Molar Masses Na 2 SO 4 142. g·mol –1 H 2 O 18.0 g·mol –1 (A) Na 2 SO 4 ·3H 2 O (C) Na 2 SO 4 ·7H 2 O (B) Na 2 SO 4 ·5H 2 O (D) Na 2 SO 4 ·10H 2 O (SA) = short answer; (FR) = free response; (TF) = true/false (U) = understanding; (A) = analysis; (G) = generalization
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Stoichiometry V–3 INDEX: V006 LEVEL: (U) ANSWER: KEYWORDS: formulas and equations ALTERNATIVE FORMAT: (SA) A compound of sodium, sulfur, and oxygen contains 29.1% Na, 40.6% S, ad 30.3% 0. What is the correct empirical formula? Atomic Molar Masses Na 23.0 g·mol –1 S 32.1 g·mol –1 O 16.0 g·mol –1 A compound of sodium, sulfur, and oxygen contains 29.08% Na, 40.56% S, and 30.36% 0. Which formula is correct? Atomic Molar Masses Na 23.0 g·mol –1 S 32.1 g·mol –1 O 16.0 g·mol –1 (A) Na 2 SO 3 (D) Na 2 S 2 O 8 (B) Na 2 SO 4 (E) Na 2 S 4 O 6 (C) Na 2 S 2 O 3 INDEX: V007 LEVEL: (A) ANSWER: KEYWORDS: formulas and equations, organic chemistry ALTERNATIVE FORMAT: (SA) Omit responses. A hydrocarbon undergoes complete
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This test prep was uploaded on 04/20/2008 for the course CHEM 105 taught by Professor F during the Fall '05 term at Grove City.

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final exam MC review file 2 - V1 SECTION V STOICHIOMETRY...

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