MAT 221 Week 3 Discussion.odt - For this discussion we are...

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For this discussion, we are supposed to find the equation of the line that are parallel or perpendicular to the given lines and which passes through the specific point. My assigned number is 19 The equation that I will be using is y=-3x-6 and the parallel line must pass through point (-3, 2). The slope of the given line is -3. So, the slope of the parallel line will also be -3. Now I know the slope of the new line and I know that the line passes through (-3, 2). I will be using the point- slope form of a linear equation to write my new equation. y – y1 = m(x – x1) This is the general form of the point- slope equation y – (2) = -3[x – (-3)] Here I substituted my known slope and ordered pair y + 2 = -3x+(-3)3 Simplifying double negatives and distributing the slope y = -3x-9-2 -3 times 3=-9 and 2 is subtracted from both sides y = -3x-11 Equation of my parallel line This line falls from left to right across the graph and the

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