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For this discussion, we are supposed to find the equation of the line that are parallel or perpendicular to the given lines and which passes through the specific point.My assigned number is 19The equation that I will be using is y=-3x-6 and the parallel line must pass through point (-3, 2).The slopeof the given line is -3. So, the slope of the parallel line will also be -3. Now I know the slopeof the new line and I know that the line passes through (-3, 2). I will be using the point-slopeform of a linear equation to write my new equation. y – y1 = m(x – x1) This is the general form of the point-slopeequation y – (2) = -3[x – (-3)]Here I substituted my known slopeand ordered pairy + 2 = -3x+(-3)3 Simplifying double negatives and distributing the slopey = -3x-9-2-3 times 3=-9 and 2 is subtracted from both sidesy = -3x-11Equation of my parallel lineThis line falls from left to right across the graph and the