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Unformatted text preview: Draw the reaction coordinate diagram and discuss why the major product is both thermodynamically and kinetically favored. The result is either the formation of 2-chloro-2-methylpropane or 1-chloro-2-methylpropane. However, since 2-chloro-2-methylpropane proceeds through a tertiary carbocationit is the major product (in this case, the only product). The reaction coordinate diagram should show the stability of the tertiary carbocation (leading to the formation of 2-chloro-2-methylpropane) at a lower energy (more stable) than the primary carbocation (leading to the formation of 1-chloro-2-methylpropane). The formation of 2-chloro-2-methylpropane is thermodyanically favored. The RCD should also show that the free energy of activation should be lower for formation of the tertiary carbocation and higher for the formation of the primary carbocation. This shows that the formation of 2-chloro-2-methylpropane is kinetically favored....
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