# HW_13_Sol - Physics 112 HW#13 Solutions Spring 2006 13.2[Oscillator a The amplitude is 0.12m b the period T will be 2x 0.8s= 1.6 s and c the

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- 1 - Physics 112 - HW #13 Solutions Spring 2006 13.2 [Oscillator] a) The amplitude is 0.12m, b) the period T will be 2x 0.8s= 1.6 s, and c) the frequency is 1/T=0.625 Hz 13.4 [Graph] Reading off the graph, we find that a) the frequency is 0.5Hz, b) the amplitude is 0.2m, and c) the period is 2.0s. 13.27 [Energy in SHM] (a) E tot = K + U = ½ mv 2 + ½ kx 2 = ½ [(0.150 kg)(0.300 m/s) 2 + (300 N/m)(0.0120 m) 2 ] = 2.84 x 10 -2 J (b) ½ k x m 2 = E tot , so x m = 2E tot k = 2( 2.84 x 10 -2 J ) 300 N/m = 1.38 cm (c) ½ m v m 2 = E tot , so v m = 2E tot m = 2( 2.84 x 10 -2 J ) 0.150 kg = 0.615 m/s 13.71 [SHM of Butcher’s Scale] (a) First we need to know the speed v 1 of the steak just before it hits the scale. Let mass of steak be M =2.20 kg and mass of pan be m = 0.200 kg. Let speed of steak just before it hits pan be v 1 . Energy is conserved as steak falls: ½ Mv 1 2 = Mgh v 1 = 2gh = 2(9.81 m/s 2 )(0.40 m) = 2.80 m/s Next we need to know the speed v 2

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## This homework help was uploaded on 04/21/2008 for the course PHYS 1112 taught by Professor Leclair,a during the Fall '07 term at Cornell University (Engineering School).

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HW_13_Sol - Physics 112 HW#13 Solutions Spring 2006 13.2[Oscillator a The amplitude is 0.12m b the period T will be 2x 0.8s= 1.6 s and c the

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