Solution to HW 11 - 2 15 n . (74 ( ) 76) 0.99 n P M x...

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1. a (74 ( ) 76) 0.99 n P M x => (| ( ) 75 | 1) 0.99 n P M x - => (| ( ) 75 | 1) 0.01 n P M x - > According to the Chebyshev Inequality, 2 15 (| ( ) 75 | 1) n P M x n - > Hence we just need 2 15 0.01 n , which is 22500 n b. when Xi is a Gaussian distribution, we know for sure that ( ) n M x is also a Gaussian with mean 75 and variance
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Unformatted text preview: 2 15 n . (74 ( ) 76) 0.99 n P M x => (| ( ) 75 | 1) 0.99 n P M x- => (| ( ) 75 | 1) 0.01 n P M x-> => | ( ) 75 | ( ) 0.01 15 15/ n M x n P n-> => 2[1 ( )] 0.01 15 n- => 2.575 15 n => 1492 n 2. 3 4...
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This note was uploaded on 04/21/2008 for the course EE 351k taught by Professor Bard during the Fall '07 term at University of Texas at Austin.

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Solution to HW 11 - 2 15 n . (74 ( ) 76) 0.99 n P M x...

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