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Solution to HW 11

Solution to HW 11 - 2 15 n(74 76 0.99 n P M x ≤ ≤ ≥...

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1. a (74 ( ) 76) 0.99 n P M x => (| ( ) 75| 1) 0.99 n P M x - => (| ( ) 75| 1) 0.01 n P M x - > According to the Chebyshev Inequality, 2 15 (| ( ) 75| 1) n P M x n - > Hence we just need 2 15 0.01 n , which is 22500 n b. when Xi is a Gaussian distribution, we know for sure that ( ) n M x is also a Gaussian with mean 75 and variance

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Unformatted text preview: 2 15 n . (74 ( ) 76) 0.99 n P M x ≤ ≤ ≥ => (| ( ) 75 | 1) 0.99 n P M x-≤ ≥ => (| ( ) 75 | 1) 0.01 n P M x-> ≤ => | ( ) 75 | ( ) 0.01 15 15/ n M x n P n-> ≤ => 2[1 ( )] 0.01 15 n-Φ ≤ => 2.575 15 n ≥ => 1492 n ≥ 2. 3 ． 4 ．...
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Solution to HW 11 - 2 15 n(74 76 0.99 n P M x ≤ ≤ ≥...

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