Solution to HW 3 - since there are 5 3 possible code words...

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Solution to ee351k hw 3 2. a. 0.8*0.8*0.2*0.2*0.2 0.00512 P = = b. 2 3 5 0.8 0.2 0.0512 3 P = * * = ,
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Unformatted text preview: since there are 5 3 possible code words with 3 ones....
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This note was uploaded on 04/21/2008 for the course EE 351k taught by Professor Bard during the Fall '07 term at University of Texas at Austin.

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Solution to HW 3 - since there are 5 3 possible code words...

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