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Ch2 Solutions Physics - Physics 195 Chapter 2 Homework...

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1. P2.3 (a) v x t = = = 10 5 m 2 s m s (b) v = = 5 1 2 m 4 s m s . (c) v x x t t = = = 2 1 2 1 5 10 2 2 5 m m 4 s s m s . (d) v x x t t = = = 2 1 2 1 5 5 4 3 3 m m 7 s s m s . (e) v x x t t = = = 2 1 2 1 0 0 8 0 0 m s Physics 195 Chapter 2 Homework Solutions 2. P2.7 (a) at t i = 1 5 . s, x i = 8 0 . m (Point A) at t f = 4 0 . s , x f = 2 0 . m (Point B) v x x t t f i f i = = = − = 2 0 8 0 4 1 5 6 0 2 4 . . . . . a f a f m s m 2.5 s m s (b) The slope of the tangent line is found from points C and D . t x C C = = 1 0 9 5 . . s, m b g and t x D D = = 3 5 0 . s, b g , v 3 8 . m s . FIG. P2.7 (c) The velocity is zero when x is a minimum. This is at t 4 s . 3. P2.11 Choose the positive direction to be the outward direction, perpendicular to the wall. v v at f i = + : a v t = = − − × = × 22 0 25 0 3 50 10 1 34 10 3 4 . . . . m s m s s m s 2 a f . 4. P2.15 x t t = + 2 00 3 00 2 . . , v dx dt t = = 3 00 2 00 . . , a dv dt = = 2 00 . At t = 3 00 . s : (a) x = + ( ) = 2 00 9 00 9 00 2 00 . . . . m m (b) v = ( ) = 3 00 6 00 3 00 . . . m s m s (c) a = 2 00 . m s 2
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5. P2.22 (a) Let i be the state of moving at 60 mi h and f be at rest v v a x x a a xf xi x f i x x 2 2 2 2 0 60 2 121 0 1 3 600 242 5 280 1 21 8 21 8 1 609 1 9 75 = + = + F H G I K J = F H G I K J F H G I K J = = − F H G I K J F H G I K J = d i b g a f mi h ft mi 5 280 ft mi h ft 1 mi h 3 600 s mi h s mi h s m 1 mi h 3 600 s m s 2 2 .
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