Ch2 Solutions Physics

Ch2 Solutions Physics - Physics 195 Chapter 2 Homework...

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1. P2.3 (a) v x t == = 10 5 m 2 s ms (b) v 5 12 m 4 s . (c) v xx tt = = =− 21 51 0 2 25 m m 4 s s . (d) v = = −− 55 4 33 m 7 s s . (e) v = = = 00 80 0 m s Physics 195 Chapter 2 Homework Solutions 2. P2.7 (a) at t i = 15 . s , x i = . m (Point A) at t f = 40 s , x f = 20 . m (Point B) v fi = = = − 20 80 41 5 60 24 .. . . . af m s m 2.5 s (b) The slope of the tangent line is found from points C and D . tx CC 10 95 s, m bg and DD 35 0 s , , v ≅− 38 . ms. FIG. P2.7 (c) The velocity is zero when x is a minimum. This is at t 4 s . 3. P2.11 Choose the positive direction to be the outward direction, perpendicular to the wall. vv a t =+ : a v t × 22 0 25 0 350 10 134 10 3 4 . . s ±ms 2 . 4. P2.15 xt t 200 300 2 , v dx dt t 300 200 , a dv dt 200 . At t = 300 s : (a) x () = 200 900 900 ... . m (b) v = = 300 600 . (c) a = . m s 2
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5. P2.22 (a) Let i be the state of moving at 60 mi h and f be at rest vv a x x a a xf xi x f i x x 22 2 2 06 0 21 2 1 0 1 3600 242 5280 1 21 8 21 8 1609 1 975 =+ F H G I K J = F H G I K J F H G I K J =− F H G I K J F H G I K J di bg a f mi h ft mi 5280±ft mi h ft 1 mi h 3600 s mi h s mi h s m 1 mi h ms 2 2 . .. . (b) Similarly, 08 0 1 64005280 422 3 600 22 2 9 94 2 ⋅ = − ⋅ =− mi h ft mi h s mi h s m s 2 af a a x x . (c) Let i be moving at 80 mi h and f be moving at 60 mi h.
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This note was uploaded on 04/21/2008 for the course BIOL 100 taught by Professor Lee during the Winter '07 term at San Diego State.

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Ch2 Solutions Physics - Physics 195 Chapter 2 Homework...

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