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nagle_phys2020_fa07_lecture19

nagle_phys2020_fa07_lecture19 - Clicker Question In the...

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1 50 Clicker Question V=12V 1 2 3 In the circuit below, what happens to the brightness of bulb 1, when bulb 2 burns out? (When a bulb burns out, its resistance becomes infinite.) A) Bulb 1 gets brighter B) Bulb 1 gets dimmer. C) It's brightness remains the same. (Hint: What happens to the current from the battery when bulb 2 burns out.) 51 Answers: Bulb 1 gets dimmer! When bulb 2 burns outs, the filament inside breaks and R2 becomes infinitely large. The total equivalent resistance which the battery sees increases (since bulb 2 is gone, there are fewer paths for the current flow, so less flow, more total resistance.) Since the battery sees a larger R-tot, the current from the battery I-tot = V/Rtot is reduced. Less current from the battery means less current through bulb 1, less light. V=12V 1 2 3 52 It is good to be able to think through (without lots of equations) how the components of these circuits work. However, we will need to use our equations to work out detailed values for current and electric potential in more complicated circuits. We now outline a systematic procedure for analyzing circuits. 53 Example 1: Choose R1 = R2 = R3 = 10 Ω V=12V 1 2 3 1. Longer line on battery is higher voltage and the shorter line is lower voltage, by convention.
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