2010_Task_3_Solutions - GENERAL MATHEan mo mac Loom...

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Unformatted text preview: GENERAL. MATHEan mo mac Loom:- AssESSMENT TA$K 3 WT Ar 6ECnON ‘ MM DD 36 @c as @3 55cm»: n W I) A: M [Oi-r)”— I] 0- $3ng 300990: M[(l+on_ 01725 6:! [7. M :. 500 900’: = $41633! 2‘) N:- M (Hr-TL] FCl-H'jn] (H—___ 0- 071550 o- 0115 I”). :Sooo[(|+0-o45)8—l ] 8 o-o45(\+o-o4s) = $ szq rm. 4% 3) a) $10000 i0 [9) AleDO “0‘5 ”'1 0'08 : $144899- 56 C) A: PCIH)n = l448b-5é2(1+0 9?st =$I45ma 28 4) a) sooox 30qu = 251545450 10) 35454-50 c) 5000 x 34515—- = $st 5454.50 l JUNE 2010 e) o)5990=M I‘o’YK—D—I <9-9"'(2<b0"(“D ______] M =Sooo o-o’TM- 0’7"j _—_-'—_-_-—__ [-OrIIQ—I =$7ll-8‘? b) $71I8-88 '1) 5: Vo(l"r)n =4500©Ct 0:417) :1 {52(556 24' 350099: loooow—iob I90 : 65000?) 9:. $05000 b) o—nooo oooabsooon 65 Deon -.—. 1000 000 = (SA—gears c) s=-voo~r)” 350000: koooooo (143‘ (tr-r)”: 0-35 u—-r :=- 96-375— r: PEG—55 30-00147 : 61.62770 94m 5 W I) C, 2) 6 3)A ADA 5)c_ SECTION 11 MM 1) a) C95: 6cm 053.5- [4-1—61 {96:12-63 Perlrhe-Per: 14+ IO+8’+1’)_.Q, 7: M-écm D) 5“ (27,62. {4 P=250 2)a)a 1.— 4552». 2301 2x 453 x 230 x C9560 (13234-61 .39) Slfi-H _. SMIBO 250 254.57 51171 H = 250 518 {3’0 134- @7 H ='12°44 ' — bearlrrlj = 360°»- {2°44‘ - 347°“; 3) a) Assoc: 18°+ 64° = 82° 19) 802: I'flzsfi 2x many cos 82° 6C: 50-9“! km 6) 1‘) cos LADD: 342+2l2l-487' 2x34x2l = -"IO‘_( [4225 (A00 : [20° ii) 255" d) A: Jix 21x23): srh 74° = 288'ekm2 z: 2649M 2b 9) Mn 9.- 22 20 7.0 9 9: 51° 2b' 18’ 1": CH5 1:) sin €— _ 5“?st [5 22 SlfiC: 65% Bio 22l r C: 20°34 AA: 12-8026 “an 1-9-1- —— 2.2. O Smi23°2g“ 5MB! 0,: 33‘46KM c) Bean'ng :: IS’O°—- 2634’ = 64°26;...
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