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Unformatted text preview: Let C do 1/c part of the job in 1 day. C could do the whole job in c days. In 1 day, working together, they do 1/a + 1/b + 1/c = 1/6 ..... (1) of the job. Similarly 1/b + 1/c = 1/9 ..... (2) and 1/a + 1/c = 1/8 ..... (3) From these three equations we solve for 1/a, 1/b and 1/c. Subtracting (3) from (1) 1/b = 1/6  1/8 = 1/24 Subtracting (2) from (1) 1/a = 1/6  1/9 = 1/18 then from (2) 1/c = 1/9  1/24 = 5/72 From these a = 18 days b = 24 days c = 72/5 = 14.4 days = 14 & 2/5 days...
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This note was uploaded on 02/27/2008 for the course MATH 116 taught by Professor Philip during the Spring '08 term at A.T. Still University.
 Spring '08
 Philip
 Algebra

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