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# exam2F06 - Tun.1 I J I-l l"L trarer slide(“misﬁts...

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Unformatted text preview: Tun-.1... I J I -l l. :"L trarer slide (“misﬁts of a 5m slope downwards at 6' = Jill“ to the horizontal followed by a 5 Inetere herizotltal etheth that ends 2.5 meters ahtn'e the water. Assuming Ire friction entl e Site-Hing of acre. how test are you trzn'ehng when you hit the 1water [in Inlet]? 'mﬁll-S 1 Sane) + [BK lo M: 5‘0 [3 il’hn*=\$0m- [1} 1n [2} [3}1t [ant-31.5 2. .31. simple pendulum eonsiete of a. Iliasﬁ. m. hanging on a. trlaeeleee String of iength L. ‘r'ral move the meet-i so that. the etrhtg L5 now at. an angle of H = 60‘ to the vertical. How much work do you need to rlo to do this? New = \$19 (ht. =0} WET: mjL{l-te£0v '- M61- _'|——.—.—.-.___— ’5 ulna P, f 1".- K a, * :h’l ad's-d (1] mfg}? mLt; [3.) EtnLyrrfS H} 0 (5) ntthh-“ﬁfﬂ 3. in he enhel starting at rest on the top of a hemispherical iglno of redqu R. slides: oﬁ' onto the erretv-emered ground. Hem- fﬁe‘l‘ l5 it going when it hits the ground“! n} he . [2} with-'3 {3} We"? H? W ‘353' R” QU-tblgao [mmzeﬁ ~m5R+ mike. V1: 2R3 L 4. Two identical blocks. each of mate'- m = 2kg. are steel-mud one above the 0|th on at table. A rope is atteehed to the lower one! and a forte F = 50?}? drag it horizontally. It Le fennel that the two hiaelte Heeelerete together at u = farm-'52. H 'What is the eo-eiﬁeient of kinetic friction m} fer the hloeltwtehle interfaee? . _ 5 F Cﬂﬁﬁldﬁ'r-E l‘l—u lbluql‘u cm; “NE F ’ mo :Aexs’; “1.0M J- ﬁecl-xrociruw n l“ E ﬂ # ll a l-Mb: 30‘? 1? 5'“: “3M NL: Pitt/IL“ 7 k [110.5 [110.75 ‘ [2} em [4104 [5}15 5. “flint is the. minimum coefﬁcient of static frietion n, for the hloelt-hleek interim in order that the two hlhelte were together? [1} of: [2} ELL} [3}1.5 [4} I14 [5} note Lual‘ a} ' . : p r r: F - I lbl“ l3? LAME: Gel: l’tur-‘tvﬁl‘etl tr“ 1;. I Help: l‘nCa 11313"th .3 5M? _ ﬁ‘ 20 ﬂ. Tm feroee. F1 and LE", art on e in kg object so that it accelerates in the r—direﬂjﬁn with :19: = amt-’5? Fl is 205. #5. 1 Cl '1‘: tlLretted at an angle of 3?: from the Jr—tiiret-tlen. What is the magnitude of F2 in New-tone? U [1} 15 [2} a [3} 15 “531 [4}9 [5} W5 h} Eat it: EK’SASN a; emcee «[1st: E1 2%} TTTTT by a force F pointing at tight {wiggles to the slope. It is found that 15" has to he at. F F least 1'35: 10 Stop Lh . bleak from slipping down the elepe. 'What E hf." N -F £2me ("(15 Smoky; 3/4, FM : {143:er : 1xlmo~6 Law (5‘) Fe: “‘3 (“Gig item-8 tie : hard 11 #13, ft : é/It coal: (1) 0.333 [2} 11.5 {3; UTE} {4] 0.6% [5} 0.375 ‘5 . T. A m = 1 kg bled: is: Sitting on a slope of 5' w 3}": m. the hormnm‘ held 'm mace [I1 8. :i. 5!] kg women is in an elevator whieh, at one moment. is moving duwtiwatti at F: speml of 3111,55 while accelerating upward-i al 9 rate of 1 111.352. 'Whet- is the magnitude of the normal three of the liner en the we:nan':' [1} 5.50): [345024 {.13 met {4] 4mm (5)5111): F“ It ‘rd 4, F' - S d" t a “at. T me : SEN m3:§oxre:\$‘ﬁe Niup} - 55rd,} (ﬁ‘fhjjma St. A ball of meat m -— 1 l-cg is whirling in a, vertical circle on a string of length I, = [15 In. :‘lt the button: of the circle the speed of the hall is, .3 mg's. What is the tension in the ﬁring when the bell is at the hortem ef the circle? l1“ T "m5 : “W 1 mil = FR L: i T: FEW : “:1 1m : 6W re R 3 E [I] 603: {2] 40M [3} \$05: [4} ‘EDN {5] l0); 1f}. ir‘i'hnr L4 the. speed of the ball when 1':- is at the top of I'll!“ circle? {1} x-ﬁmfe [2} 41113: (3) 3 lit-'5 («1} lmfs {5] 2.5 [rife {SD ‘l‘ 3K 5 with? f D Elﬁn-1.3 Club-£5 ne murh) 1;? m ‘3 1R + AK‘D; {3K “lg 1: 11. A block el‘ mass m. = 3kg ie an :1 table and attached to :1 string which gees ever 2 1. mt! 1* 14% ’4‘ H- maﬁlees nullity to e eede hlticlt mg. Them is no friction. and the him-J: an the 3 kg 4—113: L l' " IT __'_ table. is set-eleteting at a = :1 mfs2. What is the temhm in the string? u 1- ; 25' - 10 l_.__ l h} E: me 5T : lx‘ﬁ-ZH-N {1] 123' (2] 4N {3135: (4) 3H {5) sax 12. What is the [Um ef the second block-mg? {1] 2kg (2) 3kg {3] “:3 {-1) 5kg [5} {3kg {th ~ T : mt q mlxlo __, = iii-(4' mL.'ull£3 a—m I In '--| 13. A Lilo-ck of mass m = 1 kg is dropped ﬁprn rest (mm a Spring, of spring constant. k = 409 N} m. The spring L1 comp-Imam a distance r = {1.1 m when the bJEU-E'k amps for an instant. HOW far did the block [all before it hit the spring? AM + ﬁK : 0‘ {NEH-r 1‘3) umﬁgrgj + am} :0 {M to) ialon[o-i+ﬂ)=§*‘rﬁbr(ﬂ1ﬁ '7 9‘ 31““ lob-113) :: l :3; j ro-im {1}0.1I1: {2] 0.2m {3] 0.4 m {4] n.5m [11 {5] 113m --4 -4 -1 ‘11 ...
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