stats 363 HW-Section-10-3

stats 363 HW-Section-10-3 - Section 10.3 Exercise 10.1. (a)...

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Section 10.3 Exercise 10.1 . ( a ) 2 : 015 ( b ) 2 : 306 ( c ) 1 : 330 ( d ) 1 : 960 Exercise 10.2 . ( a ) A two-tailed test with = 0 : 01 and 12 df gives t 2 = t 0 : 005 = 3 : 055. The rejection region is j t j > 3 : 055; that is, either t < 3 : 055 or t > 3 : 055. ( b ) A right-tailed test with = 0 : 05 and 16 df gives t = t 0 : 05 = 1 : 746. The rejection region is t > 1 : 746. ( c ) A two-tailed test with = 0 : 05 and 25 df gives t 2 = t 0 : 025 = 2 : 060. The rejection region is j t j > 2 : 060; that is, either t < 2 : 060 or t > 2 : 060. ( d ) A left-tailed test with = 0 : 01 and 7 df gives t = t 0 : 01 = 2 : 998. The rejection region is t < 2 : 998. Exercise 10.3 . ( a ) A two-tailed test with t = 2 : 43 and 12 df : The p -value is given by p -value = P f t < 2 : 43 g + P f t > 2 : 43 g = 2 P f t > 2 : 43 g : Then it is clear that 1 2 ( p -value) = P f t > 2 : 43 g : Now we read from Table 4 that P f t > 2 : 179 g = 0 : 025 P f t > 2 : 43 g = 1 2 ( p -value) P f t > 2 : 681 g = 0 : 010 : It follows that 0 : 01 < 1 2 ( p -value)
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This note was uploaded on 04/20/2008 for the course MTH 1363 taught by Professor Cheng during the Spring '08 term at Creighton.

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stats 363 HW-Section-10-3 - Section 10.3 Exercise 10.1. (a)...

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