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spring08 key 4 - N = 175 q =males =.45 males = 93 1-tailed...

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ANTH 4000/5000 Spring 08 Homework Key 4 1.) Since Ho states that p = q = 0.5, you can use Table D. Look up the probability of an N of 19 and an x of 6 (the smaller counterpart to 13) = .084 .084 > .05 Therefore, Ho retained, p > 0.05 You can also use chi-square or the long-form binomial. You can’t use the z-transformation of the binomial because Npq is less than 9. Here’s the 2 χ : H 0 : Probability of liberals = 0.5 H 1 : Probability of liberals > 0.5 1-tailed α = 0.05 df = K (categories) – 1 = 1 CVχ 2 = 2.71 2 χ = = - k i e o e f f f 1 2 ) ( = 5 . 9 ) 13 5 . 9 ( 2 - + 5 . 9 ) 6 5 . 9 ( 2 - = 2.58 2.58 < 2.71 H O retained, p > 0.05 2.) p = survival = .2 q = failure = .8 P (1) = 15pq 14 = 15(0.2)(0.8 14 ) = 0.1319 P (0) = q 15 = 0.8 15 = 0.0352 Probability that they won’t survive is 0.1671 or 16.71%. 3.) H O : females = 0.55 H 1 : females < 0.55 p = females = .55 females = 82
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Unformatted text preview: N = 175 q =males = .45 males = 93 1-tailed test = 0.05 CV = 1.65 z-transformation of binomial because variance Npq = 43.31 (which is greater than 9) μ = NP = 96.25 σ = Npq = 6.58 09 . 2 58 . 6 25 . 96 5 . 82 ) 5 . (-=-=-± = Npq Np x z 2.09 > 1.65 ∴ H O rejected, p < 0.05 9.5 9.5 13 6 4.) H O : Sample site distribution = Previous site distribution H 1 : Sample site distribution ≠ Previous site distribution 2-tailed α = 0.05 df = K – 1 = 2 CVχ 2 = 5.99 2 χ = ∑ = -k i e o e f f f 1 2 ) ( = 5 . 10 ) 8 5 . 10 ( 2-+ 44 . 13 ) 21 44 . 13 ( 2-+ 06 . 18 ) 13 06 . 18 ( 2-= 6.27 6.27 > 5.99 ∴ H O rejected, p < 0.05 10.5 13.44 8 21 13 18.06 Upland bluff Holocene terrace Alluvial fan...
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