problem24_11

University Physics with Modern Physics with Mastering Physics (11th Edition)

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Unformatted text preview: 20 20 = = 6.56 10 -11 F/m. ln (rb ra ) ln (3.5 mm / 1.5 mm) b)The charge on each conductor is equal but opposite. Since the inner conductor is at a higher potential it is positively charged, and the magnitude is: 20 LV 20 (2.8 m)(0.35 V) Q = CV = = = 6.43 10 -11 C. ln ( rb ra ) ln (3.5 mm 1.5 mm ) 24.11: a) C L = ...
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