problem24_24

University Physics with Modern Physics with Mastering Physics (11th Edition)

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Unformatted text preview: 24.24: a)  V = Q / C = (2.55 μC) (920 × 10−12 F) = 2772 V. b) Since the charge is kept constant while the separation doubles, that means that the capacitance halves and the voltage doubles to 5544 V. 2 −12 2 −3 c)  U = 1 CV = 1 (920 × 10 F)(2772 V) = 3.53 × 10 J. Now if the separation 2 2 is doubled, the capacitance halves, and the energy stored doubles. So the amount of work done to move the plates equals the difference in energy stored in the capacitor, which is 3.53 × 10 −3 J. ...
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This document was uploaded on 04/20/2008.

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