problem24_30

University Physics with Modern Physics with Mastering Physics (11th Edition)

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24.30: a) If the separation distance is halved while the charge is kept fixed, then the capacitance increases and the stored energy, which was 8.38 J, decreases since . 2 2 C Q U = Therefore the new energy is 4.19 J. b) If the voltage is kept fixed while the separation is decreased by one half, then
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Unformatted text preview: the doubling of the capacitance leads to a doubling of the stored energy to 16.76 J, using , 2 2 CV U = when V is held constant throughout....
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This document was uploaded on 04/20/2008.

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