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24.30:
a) If the separation distance is halved while the charge is kept fixed, then the
capacitance increases and the stored energy, which was 8.38 J, decreases since
.
2
2
C
Q
U
=
Therefore the new energy is 4.19 J.
b) If the voltage is kept fixed while the separation is decreased by one half, then

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**Unformatted text preview: **the doubling of the capacitance leads to a doubling of the stored energy to 16.76 J, using , 2 2 CV U = when V is held constant throughout....

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