University Physics with Modern Physics with Mastering Physics (11th Edition)

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24.58: a) . 2 2 eq C C C C = + = So the total capacitance is the same as each individual capacitor, and the voltage is spilt over each so that 480 = V V. Another solution is two capacitors in parallel that are in series with two others in parallel.
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Unformatted text preview: b) If one capacitor is a moderately good conductor, then it can be treated as a “short” and thus removed from the circuit, and one capacitor will have greater than 600 V over it....
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