problem24_63

University Physics with Modern Physics with Mastering Physics (11th Edition)

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24.63: a) Reducing the furthest right leg yields ( 29 = + + = - 1 F 9 . 6 1 F 9 . 6 1 F 9 . 6 1 μ C . 3 / F 3 . 2 1 C μ = It combines in parallel with a . F 9 . 6 F 3 . 2 F 6 . 4 1 2 C μ μ μ C C = = + = So the next reduction is the same as the first: . 3 / F 3 . 2 1 C μ C = = And the next is the same as the second, leaving 3 1 C ’s in series so . 3 / F 3 . 2 1 eq C μ C = = b) For the three capacitors nearest points a and b: C 10 9.7 V) (420 F) 10 3 . 2 ( 4 6 eq 1 - - × = × = = V C Q C and . C 10 6.44 3 V) (420 F) 10 6 . 4 ( 4 6 2 2 2 - - × = × = = V C Q C c) ( 29 , V 46.7 V 3 420 3 1 = = cd V since by symmetry the total voltage drop over the
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This document was uploaded on 04/20/2008.

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