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24.63:
a) Reducing the furthest right leg yields
(
29
=
+
+
=

1
F
9
.
6
1
F
9
.
6
1
F
9
.
6
1
μ
C
.
3
/
F
3
.
2
1
C
μ
=
It combines in parallel with a
.
F
9
.
6
F
3
.
2
F
6
.
4
1
2
C
μ
μ
μ
C
C
=
=
+
=
⇒
So
the next reduction is the same as the first:
.
3
/
F
3
.
2
1
C
μ
C
=
=
And the next is the same as
the second, leaving 3
1
C
’s in series so
.
3
/
F
3
.
2
1
eq
C
μ
C
=
=
b) For the three capacitors nearest points a and b:
C
10
9.7
V)
(420
F)
10
3
.
2
(
4
6
eq
1


×
=
×
=
=
V
C
Q
C
and
.
C
10
6.44
3
V)
(420
F)
10
6
.
4
(
4
6
2
2
2


×
=
×
=
=
V
C
Q
C
c)
(
29
,
V
46.7
V
3
420
3
1
=
=
cd
V
since by symmetry the total voltage drop over the
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