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Unformatted text preview: obaidi (aao476) OH13 Bradley (191) 1 This printout should have 22 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. This is Online Homework No. 13 (OH13). It is due Thursday morning (27 Nov) at 7:00 AM (UAE time). 001 10.0 points A harmonic wave is traveling along a rope. The oscillator that generates the wave com pletes 41 . 0 vibrations in 29 . 5 s. A given crest of the wave travels 391 cm along the rope in a time period of 10 . 8 s. What is the wavelength? Correct answer: 0 . 26049. Explanation: Let : n = 41 . 0 vibrations , t = 29 . 5 s , x = 391 cm , and t = 10 . 8 s . = v f = x t n t = xt n t = (391 cm)(29 . 5 s) 41 (10 . 8 s) 1 m 100 cm = . 26049 . keywords: 002 (part 1 of 3) 4.0 points A transverse wave of frequency 35 Hz propa gates down a string. Two points 15 cm apart are out of phase by 7 3 . What is the wave length of the wave? Correct answer: 12 . 8571 cm. Explanation: Let : x = 15 cm and = 7 3 . Let the positive x direction be the direction of propagation of the wave. The phase difference is = 2 x = 2 x = 2 15 cm 7 / 3 = 12 . 8571 cm . 003 (part 2 of 3) 3.0 points At a given point, what is the phase difference (as a multiple of ) between two displace ments for times 10 ms apart? Correct answer: 0 . 7 . Explanation: Let : t = 10 ms = 0 . 01 s and f = 35 Hz . The period is T = 1 f , so the phase difference is = 2 t T = 2 tf = 2 (10 ms) parenleftbigg 1 s 1000 ms parenrightbigg (35 Hz) = . 7 . 004 (part 3 of 3) 3.0 points What is the wave velocity? Correct answer: 4 . 5 m / s. Explanation: v = f = (35 Hz) (12 . 8571 cm) parenleftbigg 1 m 100 cm parenrightbigg = 4 . 5 m / s . keywords: 005 10.0 points The figure shows two wave pulses that are approaching each other. obaidi (aao476) OH13 Bradley (191) 2 P Q Which of the following best shows the shape of the resultant pulse when the centers of the pulses, points P and Q , coincide? 1. 2. 3. 4. correct 5. Explanation: Notice that the two pulses have the same width and amplitude. Choosing the the point P (the same as point Q when the two pulses coincide) as the origin, the two pulses can be described as: P : y 1 = A , d x d Q : y 2 = braceleftBigg A , d x < A , < x < d Using the principle of superposition, the re sultant pulse is y = y 1 + y 2 = braceleftbigg 2 A , d x < , < x < d P Q P + Q 006 10.0 points A 3 . 2 kg block supported by a string rests on a frictionless incline. The length of the string is 0 . 5 m and its mass of 1 . 6 g is much less than 3 . 2 kg....
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This note was uploaded on 02/16/2009 for the course PYHS 191 taught by Professor Curtise during the Spring '08 term at Abilene Christian University.
 Spring '08
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