13 - obaidi (aao476) OH-13 Bradley (191) 1 This print-out...

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Unformatted text preview: obaidi (aao476) OH-13 Bradley (191) 1 This print-out should have 22 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. This is Online Homework No. 13 (OH-13). It is due Thursday morning (27 Nov) at 7:00 AM (UAE time). 001 10.0 points A harmonic wave is traveling along a rope. The oscillator that generates the wave com- pletes 41 . 0 vibrations in 29 . 5 s. A given crest of the wave travels 391 cm along the rope in a time period of 10 . 8 s. What is the wavelength? Correct answer: 0 . 26049. Explanation: Let : n = 41 . 0 vibrations , t = 29 . 5 s , x = 391 cm , and t = 10 . 8 s . = v f = x t n t = xt n t = (391 cm)(29 . 5 s) 41 (10 . 8 s) 1 m 100 cm = . 26049 . keywords: 002 (part 1 of 3) 4.0 points A transverse wave of frequency 35 Hz propa- gates down a string. Two points 15 cm apart are out of phase by 7 3 . What is the wave length of the wave? Correct answer: 12 . 8571 cm. Explanation: Let : x = 15 cm and = 7 3 . Let the positive x direction be the direction of propagation of the wave. The phase difference is = 2 x = 2 x = 2 15 cm 7 / 3 = 12 . 8571 cm . 003 (part 2 of 3) 3.0 points At a given point, what is the phase difference (as a multiple of ) between two displace- ments for times 10 ms apart? Correct answer: 0 . 7 . Explanation: Let : t = 10 ms = 0 . 01 s and f = 35 Hz . The period is T = 1 f , so the phase difference is = 2 t T = 2 tf = 2 (10 ms) parenleftbigg 1 s 1000 ms parenrightbigg (35 Hz) = . 7 . 004 (part 3 of 3) 3.0 points What is the wave velocity? Correct answer: 4 . 5 m / s. Explanation: v = f = (35 Hz) (12 . 8571 cm) parenleftbigg 1 m 100 cm parenrightbigg = 4 . 5 m / s . keywords: 005 10.0 points The figure shows two wave pulses that are approaching each other. obaidi (aao476) OH-13 Bradley (191) 2 P Q Which of the following best shows the shape of the resultant pulse when the centers of the pulses, points P and Q , coincide? 1. 2. 3. 4. correct 5. Explanation: Notice that the two pulses have the same width and amplitude. Choosing the the point P (the same as point Q when the two pulses coincide) as the origin, the two pulses can be described as: P : y 1 = A ,- d x d Q : y 2 = braceleftBigg A ,- d x <- A , < x < d Using the principle of superposition, the re- sultant pulse is y = y 1 + y 2 = braceleftbigg 2 A ,- d x < , < x < d P Q P + Q 006 10.0 points A 3 . 2 kg block supported by a string rests on a frictionless incline. The length of the string is 0 . 5 m and its mass of 1 . 6 g is much less than 3 . 2 kg....
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This note was uploaded on 02/16/2009 for the course PYHS 191 taught by Professor Curtise during the Spring '08 term at Abilene Christian University.

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13 - obaidi (aao476) OH-13 Bradley (191) 1 This print-out...

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