Quiz5Solution - Solution a b 1/s 1/s’=1/f Here focal...

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Quiz Week 5 You want to form an erect virtual image that is 1/4 the height of the object using a thin divergent lens the focal length of which is 50 cm. (a) Draw a principal ray diagram (b) At what distance from the lens should the object be placed?
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Unformatted text preview: Solution a) b) 1/s+1/s’=1/f Here focal length f<0 and image position s’<0 while object position s>0. Also, magnification is larger than zero which gives s’=-s/4. Here is the equation 1/s-4/s=-1/50 which gives s=150 cm. f f...
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