Unformatted text preview: most distant from the central bright fringe occur? Solution a) d sin = m therefore m /d =sin &lt;1 /d ==585x10-9 /0.0116x10-3 = 0.05431 m max &lt;d/ =1/0.05431=19.8 m max = 19 Total number of fringes including the central one is 2 m max +1=39. b) Max. angle sin max =m max /d = 19/19.8=0.959 max =73 degrees...
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This note was uploaded on 02/17/2009 for the course PHY na taught by Professor Richardscalettar during the Spring '09 term at UC Davis.
- Spring '09