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A Submarine Adventure: Density Saves the Day Lab

# A Submarine Adventure: Density Saves the Day Lab - Data and...

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Data and Results Part I: Determining the density of a metal cylinder Part II: Submarine Adventure Mass of graduated cylinder 39.0834 g Volume of ocean water 2.10 mL Mass of water 2.143 g Weight of balloon w/weights 138.590 g Density of ocean water 1.020 g/mL Volume of balloon needed to match 135.804 cm^3 Final volume of submarine 95.950 cm^3 Final density of submarine 1.45 g/mL

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Calculations In order to find the volume of the metal cylinders, volume by measurement would work with the formula: V metal cylinders = ╥ r 2 h V metal cylinder 1 = ╥ (1.24) 2 (0.575) = 2.778 cm 3 V metal cylinder 2 = ╥ (0.622) 2 (5.10) = 6.209 cm 3 Mass of the water can be found by subtracting the mass of the 10mL graduated cylinder from the mass of the graduated cylinder with water. Mass water = 41.226g-39.083g= 2.143 g The density of the “ocean water” can be found through this formula: Density ocean water = grad. cylinder with water mass(g)- grad.cylinder mass(g) Volume of “ocean water”(mL) = 41.226g-39.083g = 1.020 g/mL 2.10 mL The volume of the balloon needed to match the salt-water density can be found through this equation: Density ocean water = Density submarine = Balloon+pellets mass(g) 4/3*╥r 3 1.020 g/mL= 138.590g r 3 = 32.437 r=3.189 d=6.378 4/3*╥r 3 mL Plug in the diameter into the volume equation and the volume of the balloon need to match the salt-water density would be 135.804 cm
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A Submarine Adventure: Density Saves the Day Lab - Data and...

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