JohnPedenECE257Exercise4 - 13 a in simulink for f(t = 5 sin...

13.
a)
in simulink, for f(t) = 5 sin ( π t – π /2) + 4:
amplitude: 5
bias: 4
frequency: pi
phase: -pi/2

>> t = 0:0.01:10;
>> y = 5 * sin(pi .* t - pi / 2) + 4;
>> plot(t, y)

b)

c)

d)

>> t = 0:0.2:10;
>> y = 3 * t + 5;
>> plot(t,y);
Yes, all 3 graphs look the same.

14.
a)
>> f = imread('rose.tif');
>> imshow(f);

>> imshow(f, [15, 150]);

>> imshow(f, [60, 100]);

>> imshow(f, [0, 55]);

b)
>> g = 255 - f;
>> size(g)
ans =
1024 1024
>> imshow(g)
The whites are now black, and the blacks are now white. This is called the negative of the original.

c)
>> f = imread('rose.jpg');
>> imshow(f);

>> imshow(f, [20, 190]);

imshow(f, [44, 202]);

>> imshow(f, [77, 240]);

>> g = 255 - f;
>> size(g)
ans =
1024 1024
>> imshow(g)

>> f = imread('lena.jpg');
>> imshow(f);
>> imshow(f, [7, 17]);

>> imshow(f, [19, 50]);
>> imshow(f, [55, 237]);

>> g = 255 - f;
>> size(g)
ans =
300 300
>> imshow(g)

>> f = imread('camearaman.jpg');
>> imshow(f);
>> imshow(f, [20, 168]);