{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

MATLAB 2 - Exercise 2.1 Exercise 2.2 a y =(exp x y(exp x 1...

Info icon This preview shows pages 1–7. Sign up to view the full content.

View Full Document Right Arrow Icon
Exercise 2.1 Exercise 2.2 a) -2 0 2 4 6 8 10 -4 -3 -2 -1 0 1 2 3 4 x y y ' = (exp( - x) - y) (exp( - x) + 1 + y)
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Dfield draws the lines based on the initial condition I provided when I clicked somewhere on the graph. b) It’s much easier to plot the direction field of a difficult or impossible differential than to actually solve it. Exercise 2.3 -2 0 2 4 6 8 10 -4 -3 -2 -1 0 1 2 3 4 x y y ' = x + y If the initial value in this problem weren’t (1,1) it wouldn’t greatly throw off the solution.
Image of page 2
Exercise 2.4 -2 0 2 4 6 8 10 -4 -3 -2 -1 0 1 2 3 4 x y y ' = y - 2 It diverges quickly so inaccuracy throws off the solution greatly.
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Exercise 2.5 0 1 2 3 4 5 6 7 8 9 10 -4 -3 -2 -1 0 1 2 3 4 t y y ' = k (A - y) A = 1 k = 3 A is the ambient temperature because all solutions of the differential equation approach it
Image of page 4
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 6
Image of page 7
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern