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Determining the Thickness of Aluminum Foil Lab Report Procedure Area In the experiment we used a precise metric ruler in order to determine the length of three aluminum foils. First, what we did was take foil number seven and straightened out the wrinkles in order to get clear measurement of the foil. Then, we took the ruler and using centimeters, we measured the length of the foil. We measured two other foils number 6 and 8 but kept the ruler the same. We also used the same precise metric ruler to measure the width of the same three foils. First, what we did was take foil number 7 and straightened it out again just to make sure that we get the most precise measurement. Then, we took the ruler and using centimeters, we measured the width of the foil. We also measured the two remaining foils to find their width. Lastly, same as the length, for us to get a precise measurement, we used precision to get an exact measurement. Mass Finally, we used an electric balance to measure the mass of each aluminum foil in grams. In order to do this we had to make sure that the electric balance was at zero, so that the measurement was precise. Then, we made sure that the foils were not folded in any area so that they did not alter the measurement. Once the electric balance was at zero, we properly arranged the foil on the electric balance and took the measurement; we did this two more times for the two other foils. Density In order to get the density of the foils, we used the formula for finding density 2
(Mass/volume). The density of aluminum was 2.70g/cm
. To find density we found the area for each of the foil; we used area because the measurement for aluminum has squared in it and squared signifies area. To find area we multiplied length x width. Once we found area, we 2
plugged in the 3 areas that we got into 2.70g/cm
3 different times. Variables, Control and Constants Independent Variable:
Aluminum Foil (#7, 8 and 6) Dependent Variable:
Length, Width, Mass and Density Control: Class Average Constants:
Type of Ruler, Brand of Aluminum Foil and the same balance beam Trials were repeated 3 times for the length, width, mass and density. Data and Calculations Foil Length (cm) Width (cm) Mass (g) #7 16.45 17.10 1.716 #8 21.98 7.89 1.056 #6 17.00 14.19 1.481 Class Comparison Formulas: V=L·W·H V=A·T V= L·W·T D=M/V A(cm²)= L·W T=V/A Width (cm) Length (cm) Area (cm²) Volume (cm³) Thickness Mass (g) Class Average 10.93 17.84 190.46 0.42 .00223253 1.15 Our Average 13.06 18.48 241.35 0.42 .001749427 1.14 Error To calculate the error (experimentalaccepted value) of the thickness of the foil that we ²we used our average thickness and the class average thickness. We entered it into the formula 
.001749427−.00223253  x 100 = 21.64%. for percent error which is experimental −accepted accepted value
.00223253
 x 100. 

Conclusion The objective of this lab was to determine the thickness of the aluminum foil and compare it to the class average. It turned out that the class average thickness was thicker than our own determined thickness (Class Average =.00223253 > .001749427 = our average). Our percent of error was 21.64%. The class average of the width was 10.93cm while our was 13.06cm. We were above the average by 2.13cm. Also, the class average length was 17.84cm while ours was 18.48cm. We were also above the class length average by 0.64cm. This affected our area and made it different to the class average. The class average was 190.46cm² while our area average was 241.35cm², causing a 50.89cm² difference between the two. This had an effect on the thickness (V/A) since our area differed from classes. By doing this lab we learned how to calculate the thickness of aluminum foil and about how a small mistake can affect our measurements. We also learned that by using more precise measurements we can find a better comparison. ...
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 Winter '16
 Mr. Michocki
 Chemistry, aluminum foil, class Average