PHYS
20160628082003physics_questions

# 20160628082003physics_questions - Physics Questions...

• Notes
• 4

This preview shows pages 1–4. Sign up to view the full content.

Physics Questions CollegeKidPoet June 28, 2016 Abstract Solve each of the following problems and show all work. 1 Practice Homework #2.1 The electrons and protons of a hydrogen atom are separated by a distance of approximately 5 . 5 * 10 - 11 m . Find the magnitude and gravitational force between the two charges. 1.1 What is the magnitude? 1.1.1 Notes Mass of an electron: 9 . 1 * 10 - 31 kg Coulomb’s Law: F m = k e | e | 2 r 2 with the following information: F m = k e | e | 2 r 2 k e = 8 . 99 * 10 9 Nm 2 C 2 e = 1 . 602 * 10 - 19 C r = 5 . 5 * 10 - 11 m Major Note: k e | e | 2 r 2 = k e | q 1 | | q 2 | r 2 1

This preview has intentionally blurred sections. Sign up to view the full version.

1.1.2 Steps F m = k e | e | 2 r 2 = 8 . 99 * 10 9 ( Nm 2 C 2 )( (1 . 6 * 10 - 19 C ) 2 (5 . 5 * 10 - 11 m ) 2 ) = [(8 . 99 * 10 9 )( (1 . 6 * 10 - 19 ) 2 (5 . 5 * 10 - 11 ) 2 )][( Nm 2 C 2 )( C 2 m 2 )] = [(8 . 99 * 10 9 )( 2 . 56 * 10 - 38 3 . 025 * 10 - 21 )][ N ] = [7 . 6 * 10 - 8 ][ N ] = 7 . 6 * 10 - 8 N 1.2 What is the gravitational force? 1.2.1 Notes Gravitational Force: 6 . 67 * 10 - 11 Nm 2 kg 2 Newton’s Law of Gravity: F g = G ( m e )( m p ) r 2 G = 6 . 67 * 10 - 11 Nm 2 kg 2 m e = 9 . 11 * 10 - 31 kg m p = 1 . 67 * 10 - 27 kg r = 5 . 5 * 10 - 11 m 1.2.2 Steps F g = G ( m e )( m p ) r 2 = (6 . 67 * 10 - 11 Nm 2 kg 2 ) (9 . 11 * 10 - 31 kg )(1 . 67 * 10 - 27 kg ) (5 . 5 * 10 - 11 m ) 2 = [(6 . 67 * 10 - 11 )( (9 . 11 * 10 - 31 )(1 . 67 * 10 - 27 ) (5 . 5 * 10 - 11 ) 2 )][( Nm 2 kg 2 )( ( kg )( kg ) m 2 )] = [(6 . 67 * 10 - 11 )( 15 . 2137 * 10 - 58 3 . 025 * 10 - 21 )][ N ] = [3 . 4 * 10 - 47 ][ N ] = 3 . 4 * 10 - 47 N 2
2 Practice Homework #2.4 Find the resultant force on exerted on q 3 if q 1 = q 3 = 6 . 0 μC , q 2 = - 3 . 0 μC , and a = 0 . 15 m . 2.1 What is the magnitude of F 23 ? 2.1.1 Notes F 23 = k e | q 1 | | q 2 | a 2 k e = 8 . 99 * 10 9 ( Nm 2 C 2 ) q 2 = 3 . 0 * 10 - 6 C q 3 = 6 . 0 * 10 - 6 C a = . 15 m 2.1.2 Steps F 23 = k e | q 1 | | q 2 | a 2 = 8 . 99 * 10 9 ( Nm 2 C 2 ) (3 . 0 * 10 - 6 C )(6 . 0 * 10 - 6 C ) (0 . 1 m ) 2 = [ ( 8 . 99 · 10 9 ) ( 3 · 10 ( - 6) ) ( 6 · 10 ( - 6) ) ( . 1) 2 ! ][( Nm 2 C 2 ) ( C )( C ) m 2 ] = [

This preview has intentionally blurred sections. Sign up to view the full version.

This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern