Discussion Question 7

# Discussion Question 7 - Discussion Question 7 Equation log...

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Discussion Question 7 Equation log 4 x + log 4 ( x 6 ) = 2 Solving for the solution ( x 6 ) ( x ) = x 2 ¿ 6m Add the same logs together meaning multiply them. log 4 ( x 2 6 m ) = 2 We can then change the log to an exponential equation. log 4 ( x 2 6 x ) = 2 = x 2 6 x = 16 = x 2 6 x Move “16” to the right and solve the equation. 16 = x 2 6 x = 16 16 = x 2 16 = 0 = x 2 6 x 16 Or x 2 6 x 16 = 0 We then look for all the factors or -16 and one of these pairs will come up with the sum of -6
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