STATS
GMAT_Flex_Quant_Mastery_B_Expl

GMAT_Flex_Quant_Mastery_B_Expl - Quant Mastery B Answers...

Info icon This preview shows pages 1–6. Sign up to view the full content.

Quant Mastery B Answers and Explanations
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

Image of page 2
3 Quant Mastery B Answers and Explanations 1. A 2. D 3. B 4. B 5. A 6. D 7. D 8. C 9. B 10. C 11. D 12. D 13. C 14. A 15. D 16. D 17. D 18. B 19. E 20. E 21. B 22. D 23. E 24. C ANSWERS AND EXPLANATIONS
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

4 Quant Mastery B Answers and Explanations 1. (A) Car X began traveling at an average speed of 35 miles per hour. After 72 minutes, car Y began traveling at an average speed of 49 miles per hour. When both cars had traveled the same distance, both cars stopped. How many miles did car X travel from the time car Y began traveling until both cars stopped? 105 120 140 147 168 Step 1: Analyze the Question Let’s start by paraphrasing the given information: Car X gets a head start, and then car Y starts driving at a faster rate until it catches up with car X. The cars’ speeds are given in miles per hour, but we’re given a time in minutes, so we’ll need to convert all of the information into the same units (probably hours). We can be sure we’re going to use the rate formula in this question. The most important rate in ques- tion, however, is not the rate of car X or of car Y alone, but rather the rate at which car Y catches up with car X. Step 2: State the Task The question asks us for the distance that X travels starting from the time that Y begins to move. We can first use the rate formula and the information we’re given to determine how much of a head start car X got. Then, we’ll calculate the speed at which car Y closed the gap and use the rate formula a second time to determine how long it took car Y to catch up with car X. Finally, we’ll use the rate formula a third time to determine how far car X traveled in that time. Step 3: Approach Strategically 72 minutes is 6 __ 5 hours. In that time, car X traveled ( 35 miles ________ hour ) ( 6 __ 5 hours ) 5 42 miles. Therefore, 42 miles is the distance of the head start that car X got. Since car Y went 14 miles per hour faster than car X, it closed the gap at a rate of 14 miles ________ hour . The 42-mile head start divided by 14 miles ________ hour gives us 3 hours—the amount of time it took car Y to catch up with car X. During those 3 hours, car X traveled ( 35 miles ________ hour ) (3 hours) 5 105 miles. The correct answer is (A) . Step 4: Confirm your Answer If you doubted your answer, you could confirm it by comparing the total distances that car X and car Y traveled, since they ended up traveling the same distance. We calculated the distances car X traveled for both legs of the trip, 42 miles and 105 miles, so car X traveled a total of 147 miles. Car Y traveled 49 miles per hour, and it took 3 hours to catch car X, so it went ( 49 miles ________ hour ) (3 hours) 5 147 miles. The distances match, confirming that (A) is correct.
Image of page 4
5 Quant Mastery B Answers and Explanations 2. (D) Q R S P In the figure above, the measure of angle PQR is 90 degrees, and the measure of angle QSP is 90 degrees. What is the area of triangle PQR  ?
Image of page 5

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

Image of page 6
This is the end of the preview. Sign up to access the rest of the document.
  • Winter '15
  • triangle, Darcy, Quant Mastery

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern