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Math1920 - = 0(c x 2 z 2 = 4 y = 0 12.1.41-The center of...

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Math 1920 - Solutions to HW0 Jan 23, 2009 12.1.1 - The line through the point (2 , 3 , 0) parallel to the z-axis. 12.1.5 - The circle x 2 + y 2 = 4 in the xy-plane. A circle of diameter 2 centered at the origin and contained in the xy-plane 12.1.10 - The circle x 2 + z 2 = 9 in the plane y = - 4. A circle of diameter 3 centered at (0 , - 4 , 0) and contained in the plane y = - 4 12.1.16 - (a) The circumference and interior of the circle x 2 + y 2 = 1 in the xy-plane (b) The circumference and interior of the circle x 2 + y 2 = 1 in the plane z = 3 (c) A solid cylindrical column of radius 1 whose axis is the z-axis. 12.1.22 - (a) x 2 + y 2 = 4 , z = 0 (b) y 2 + z 2 = 4
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Unformatted text preview: = 0 (c) x 2 + z 2 = 4 , y = 0 12.1.41 -The center of the circle is at the point (-2,0,2). The radius is r = 2 √ 2 . Reference Figure 12.6. 12.1.55 -Given a point P ( x,y,z ), the distance to the (a) x-axis is d = p y 2 + z 2 . Where the point on the x-axis is P 1 ( x, , 0). (b) y-axis is d = √ x 2 + z 2 . Where the point on the y-axis is P 1 (0 ,y, 0). (c) z-axis is d = p x 2 + y 2 . Where the point on the z-axis is P 1 (0 , ,z ). Found using the distance formula d = p ( x 1-x ) 2 + ( y 1-y ) 2 + ( z 1-z ) 2 1...
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