Report for Lab M5

Report for Lab M5 - LAB REPORT FOR M5 EXPERIMENT: NEWTONS...

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LAB REPORT FOR M5 EXPERIMENT: NEWTON’S 2 nd LAW The premise for this lab was to investigate Newton’s second law of motion that states a F m = . To do this we used an apparatus that looks like this: Using these measurements and performing the experiment well, we can calculate acceleration of the system as well as the acceleration due to gravity. VI-2: In V-2 we obtained a series of values of t and s for fixed values of M 2 and M T . This was done by varying . My data for V-2 is tabulated below: (cm) 1 t (s) 2 t (s) 3 t (s) 4 t (s) t (s) t σ (s) ( 29 2 t (s 2 ) ( 29 2 d d s - + = (cm) 5 0.1222 0.1226 0.1221 0.1238 0.12267 5 0.00078 0 0.01505 0.1926 10 0.2375 0.2384 0.2468 0.2399 0.24065 0 0.00421 8 0.05791 0.7180 20 0.4611 0.4546 0.4441 0.4440 0.45095 0 0.00839 8 0.20336 2.5403 30 0.6929 0.6877 0.6946 0.6969 0.69302 5 0.00391 0 0.48028 5.1472 Mass on hanger, M = 10.0 g M 1 = M(glider) + M(5 cm flag) + M(10 cm flag) + M(20 cm flag) + M(30 cm flag) = 547.8 g M 2 = M + M(weight hanger) = 15.5 g Start position of glider rear end on the air track: L = 120.2 cm Final position of glider rear end on the air track: L’ = 90.2 cm d = L – L’ = 30.0 cm From the data in the table I was able to create a graph of s vs. ( 29 2 t . The data points create a straight line with a slope that is equal to acceleration/2 from which I was able to calculate acceleration. The graph below was created using EXCEL and the equation of the line of best fit was found using the LINEST function. EXCEL returned the following results: ( 29 2 t s 0.01505 0.19259 3 0.05791 0.71796 7 1
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0.20336 2.54033 3 0.48028 5.14718 6 Slope 11.0054 4 0 Intercept Uncertainty in Slope 0.37743 7 N/A Uncertainty in Intercept Ave. time squared vs. delta s y = 11.005x 0 1 2 3 4 5 6 0 0.1 0.2 0.3 0.4 0.5 0.6 Ave. time squared (sq. seconds) Delta s (cm From equation 1b in the manual we can show the equation of the line in terms of ( 29 2 t s and a . The equation of this line is: ( 29 2 2 t a s = where y = s , x = ( 29 2 t and slope = a /2. Using the slope calculated by EXCEL I was able to calculate acceleration as well as the uncertainty in acceleration. Slope of line on graph = 11.005
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Report for Lab M5 - LAB REPORT FOR M5 EXPERIMENT: NEWTONS...

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