REPORT FOR LAB T1: SPECIFIC HEAT OF METALS
In order to calculate the specific heat for the two metal samples (copper and aluminum) I first need to plot
resistance versus time for each sample based on the data taken in lab. Once this is accomplished I can
interpolate the initial and final resistance from which I can determine the initial and final temperatures.
VI1:
COPPER SAMPLE
M
M
= 1203.8gm
M
c
= 47.0gm
M
w
= 132.6gm
From my plot for copper on the following page I’ve interpolated my initial and final resistances as follows:
R
i
= 77000 ohms
R
f
= 142000 ohms
The formula to find temperature from resistance is as follows for both temperatures: where R
1
and R
2
are
temperatures corresponding to the table in the manual.
2
1
1
1
)
(
R
R
R
R
T
R
T
i
i


+
=
Ω

Ω
Ω

Ω
+
°
=
Ω
75903
79422
77000
79422
30
)
77000
(
C
T
C
C
T
°
+
°
=
Ω
69
.
0
30
)
77000
(
C
T
i
°
=
69
.
30
2
1
1
2
)
(
R
R
R
R
T
R
T
f
f


+
=
Ω

Ω
Ω

Ω
+
°
=
Ω
139610
146580
142000
146580
17
)
142000
(
C
T
C
C
T
°
+
°
=
Ω
66
.
0
17
)
142000
(
C
T
f
°
=
66
.
17
Using the values for initial and final temperature I can now calculate the heat of each component which will
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
This is the end of the preview.
Sign up
to
access the rest of the document.
 Fall '08
 SHI
 Physics, Thermodynamics, Resistance, Heat, 0.0047 cal, 0.0112 cal

Click to edit the document details