This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.View Full Document
Unformatted text preview: REPORT FOR LAB T1: SPECIFIC HEAT OF METALS In order to calculate the specific heat for the two metal samples (copper and aluminum) I first need to plot resistance versus time for each sample based on the data taken in lab. Once this is accomplished I can interpolate the initial and final resistance from which I can determine the initial and final temperatures. VI-1: COPPER SAMPLE M M = 1203.8gm M c = 47.0gm M w = 132.6gm From my plot for copper on the following page Ive interpolated my initial and final resistances as follows: R i = 77000 ohms R f = 142000 ohms The formula to find temperature from resistance is as follows for both temperatures: where R 1 and R 2 are temperatures corresponding to the table in the manual. 2 1 1 1 ) ( R R R R T R T i i-- + = - - + = 75903 79422 77000 79422 30 ) 77000 ( C T C C T + = 69 . 30 ) 77000 ( C T i = 6 9 . 3 0 2 1 1 2 ) ( R R R R T R T f f-- + = - - + = 139610 146580 142000 146580 17 ) 142000 ( C T C C T + = 66 . 17 ) 142000 ( C T f = 6 6 . 1 7 Using the values for initial and final temperature I can now calculate the heat of each component which will allow me to calculate the specific heat of the copper sample from the equation Q...
View Full Document