BonusQuiz[Fall_2010-2011] - Solution for Quiz —Bonus#3...

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Unformatted text preview: Solution for Quiz —Bonus (#3) Work — Energy Physics I Fall 2010 Physics I . Quiz —Bonus (#3) Work - Energy . Fall 2010 Problem (1) A 65 kg ski starts from rest and slides down a 22.0° incline 75.0 m long .(a) If the coefficient of kinetic friction is 0.09, used the work —energy method to find the ski’s speed at the base of the incline? (b) If the snow is level at the foot of the incline and has the same coefficient of kinetic friction, how far will the ski travel along the level? Use energy methods. 'L i , KL 1 L1 k v,‘ , mafia». Cm? "\‘1—‘\i\%rlkwus* within) #41 — -~ kl) may “*3 S-Crsér/ \QgVK%-:. oto—b/ " “m3: K33_14k°\0~5) . 312$ vim-om—yi‘séwmn/ “a; = \1‘5‘31? :5 :2. ‘gsas-iv/ kw\<i>~;\5(0, EZF‘HK PM nae) 5 ? Ross ea ans» new = tonew«Kelsi-side) L- NS"- —l°sz>€3 _ (An = mg C43? 2° Sixes? 1%, A“ \ \13 $>V\’%>Y~ I», {A \ \P'L : %¢\Y_kfi¢<uk‘lv $3500: "k 58 k—O 9- Vb— 23-36% DJ \ki . g :+ _. “k3 'k b): Vm“ Ik<3-\_ \: \<‘L'\*R°NL \ z, % 3 Nvuxl<wgkkem= L M\F_\ 6 ® , “ “We: M39C=$3(‘ .3 TR 1.“ 5g?“ :> 5 / 11:1 ~ 1 k : M-B . NS: _. _ PMBX \ S S \A f; -———-——-——-— '3 ‘ZUE5 “k @kwmkck‘k) Problem (2) A 3.0 kg object starts from rest at position A on a rough surface plane that has inclination angle of 30° as shown 1n Figure below Upon reaching bottom (position B), the object slides along a rough horizontal surface. If the coefficient of kinetic friction between the object and both incline and horizontal surfaces are equal to 0.2. Used Energy method to: (a)F 1nd the speed of the block at the bottom of the inclined plane. (b)Determine the distance (3) that the block will slide on the rough horizontal surface before coming to rest at C. TB_—\i}— QuME+NS +{EF3 ”Y“ 1 ’““Q ("limo“g Ngfigskfi/ Kw. :\> :‘do-%’, 51> b3“; =k'33cq-Kuiqwsgqv393 __— Pkg-k1? 5 ’1 SF 95%: MN. 31K? :thac‘ga/ #:l‘éc WW3 Wm memo-— 111mm 111%)ng 1~ >:— 61 KM: 5451;: E15953? :9) $.11»an 5?: <3?) $UJ9’slv.i_-c:k\ “23$ V‘gz 4%D7‘M‘Q‘HW “1° , Vw <6 ”firm/s “Pu —- ES Car-1P —.., stats: of l . ”3:“- 3:51 Ms :11: 3.1113 122129 30 -— Wk ~:. J— - \ 11:3 5 MV \MVK / 13$“ :1 5/ ohm W :t 1' '1 2 ~‘1‘m s— —‘l mVl ’ V12 » Q2511? F3 — i Ex "if", '1 ———— ST—lct‘mvx ' LS (UKO’QKQ‘U / —— Problem (3) The car (mass 3000kg) shown in the Figure below slides (wheels locked) down a frictionless incline that is 10 m long. It starts from rest at point A, and continues along a rough surface until it comes to a complete stop at point C. If the coefficient of kinetic friction between the ambulance and the horizontal rough surface is 0.1. (a) Calculate the speed of the ambulance at point B. (b) Compute the distance d the ambulance slides on the horizontal rough surface before stopping. ‘fl 1/ M3 — M3 sash tum é? : C3045 M ‘— Q9733“: CAKC'VQKN] CzsRCd-a ~30) : lit-70003 V Y\ 1 . h :3 CD§+ .2 5’ . .‘_§;\L\_l_§s.<u$_:r_%o Problem (4) A 10.0 kg crate slides with initial speed of 8.0 m/s a distance 6.0 m along a upper horizontal rough surface before reaching the point A. The crate continues to slide down a frictionless incline and across a lower horizontal surface at point B as shown in Figure below . If the coefficient of kinetic friction between the crate and the upper horizontal rough surface is 0.2. Used energy methods to: I (a) Find the speed of the crate at the point A. (b) Compute the speed of the crate at the point B. +=+ ‘ m +__ Lat.) LG W K "L ‘ L r. “'13 “’f n‘l‘ 4: a KL: “'Lva—h TM‘Jl $‘L‘085t'13w1k4‘x \'\I\ §=D\ LO Ll 7‘ c k . i - A4J+ ‘flht (LE : LMVL“ “L M\I7: ~ ~—' m \r‘xkqvq LA} _ M 2‘ I Lrj— 33%:53 —O,$vk\s; L’PiSo K - _ n V\ Egg-cf :0 I $9“ng {#139 LA . - - age. - was / xi: — 7 J A " . See-swash rem w N—u in ‘ Z L Q "7 0 \1<\V\5 S -: _;__w\ \IR— Lx‘ik‘si.‘ / \r A: \‘R a ’D—l‘d s A Lei“ c (Like-13km] to “-45 ~; “A5 S ggge5b_b) k’L :. -\ 1 \ ‘L . . ,Zkvx‘le-s. TKUB Ki ~_ L \Al 1 s-onfihirk w <66? “a exam = % \\ fit: {\ \ L r‘ i :\ ERRED ‘ . i . . - :‘(x .. e - m‘r — A, “mum—Pp a-sv—h ' .. r , . exit ~ . 'Qg.__\1?—-fi3\v\+\la v: fibrlkeo‘q (g3 4:,— (g—(‘fiy/ \‘ g :§3¢:£, mm- Problem (5) A block of mass 50 kg is pushed 6.0 m at constant speed up a rough incline by a constant force P. The pushing force is parallel to the incline, which makes an angle of 30.0° with the horizontal, as shown in Figure below .The coefficient of kinetic friction between the block and the incline surface is 0.20. (a) Calculate the magnitude of the applied force P. (b) Find the work done by the applied force P on the block. (c) Determine the work done by gravity on the block. ((1) How much energy was dissipated by the frictional force acting on the block? flu-3 (<9 it: :o "SIutCSL Vzcgw'sfifi S3 — :0. 25%.“) :3 1) N3 Sluxb. fPKKjG-w ——_ m3 Esme; 1— [1.95 a} ‘2. (€73 (cpl?) E$in 3; "l‘ Q0 ‘2.) (9520)] FF @ (fly:?'54é¢/ kirk CF ... LR)? —-_ figaqug) Egg 0]- L0 _ : 3'50N \ __.u (99 m; 2 a kwfk, {\31\%TJ / gt: FFEl: T‘kvika‘CfiS-e) . _, a. LA ”(‘4 WK ( _. . é? —‘ in 393 D\\>\ Refine} 1 Q'z—Ekga flex-sq K9: as} Leybfi “”5 2—33-17: M c? .9.- Problem (6) A 4 0kg block 18 given an initial speed of 8. 0111/5 at the bottom of a 20. 0° incline. The frictional force that retards its motion is 15. ON (a) If the block 15 directed up the incline, how far does it move before stopping? (b) Will it slide back down the incline? Explain? “5: “35 C's‘i’ k,“ ‘i $016) s (.1 to ‘ M =M$QA§afio g " SEQ” Lk\‘i>:\‘(b, <0, (,3; _ ‘3? U ) mm: “SQS¢‘0 s;¢,\¢?_g _ S. VL=°, OEJKJ O M 33 QSkaafio) __ g S 4—0 .: 0 __ K K ELM C1: 1. ikv‘ - S .- Qd to £35 *1 __ ZMV‘L \ ‘ «m? Q \ (Mafiw‘g) Eo.3\\3 ~1§ p P w L’ M 6' l 11 9’0 l ...
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