Midterm[Spring_2009-2010] - Applied Physics Department...

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Unformatted text preview: Applied Physics Department Semester: Spring 2010 College of Sciences Date: March 16, 2010 University of Sharjah Time: 3:45 —5:0 0 pm Physics (1) (1430115) Mid Term Examination Instructor: Dr.Najeh |:| Dr. Ala |:] Dr. Atta |:| Student Name Magatxffiw Student ID number : ....... Section number : ......... I Mark Assigned Mark Obtained Please read the followin instructions carefull : o This exam is made up of 7 pages, including the cover page 0 The examination consists of two paitsz. El Part I Multiple Choice Question (MCQ), please make sure you indicate your choice. a Part II Essay Questions : answer Three out of four questions. 0 Notes and books are not allowed. However, formulas and information you might need are given in a separate sheet of paper I Calculators are permitted . Dictionaries of any type are not allowed. 0 If you have questions, ask only the instructor of your course only. Part 1 - Multiple Choice Question (9 points) Choose the one alternative that best completes the statement or answers the question. MCQ] -The table gives the x and y components of two vectors A and B: x component com onent (a) The vector A-B has no x component ,3 — = 9‘0 J ,7 Why of the following statements cenceming these vecto s is true? A «(l O ‘4’ l . (b) The two vectors have different magnitudes. X S “W ‘ ° . K:— 3 o (0) Vector A makes a 56° angle with positive x axis. >4 M“ j:‘l ‘3 if ‘ I: (d) Vector B makes a 34° angle with the positive y axis. k mm.” l 3 C i -- 5 . (e) The vector A+B makes a 34° angle with the positive x axis. A ~l' " 00* .g/ X‘ ”7“ “Wm MCQZ- A truck is moving at constant velocity. Inside the storage compartment, 1a rock is dropped from the midpoint of the ceiling and strikes the floor below .The rock hits the floor (a behind the midpoint of the ceiling @ exactly below the midpoint of the ceiling / (c) ahead of the midpoint of the ceiling (d) more information is needed to solve this problem (e) none of these MCQS- If a freely falling object were somehow equipped with a speedometer, its speed reading would increases each second by about i (a) 15 m/s a hmsu'va ‘IOm/s 6" \/ (c) a variable amount (d) 5 m/s (e) depends on its initial speed 1045 [5 2 3 MCQ4—A racecar, traveling at constant speed, makes one lap around a circular track of radius R in a time t. When the car has traveled halfway around the track, what is the magnitude of the car’s displacement from the starting point? . ___2 A; X i: RR la: in-“ A 29 Tl: @R \/ :(,RC‘ @L\ (d) 215R ‘ (e) zero meters MCQS-An object moves in the xy plane with an acceleration that has a positive x component. At time t=0 the object has a velocity given v = 3i + Oj . What can be concluded about the y component of the acceleration? 0t V —- 3 0 1 a — .. (a) The y component must be positive and constant. X1 X 0&1, ’ 7 OLV w' 7' VDY 1: O l (b) The y component must be negative and constant. ‘30 ‘2‘“ 3 W (c) The y component must be zero. gird. i) /\/ .Nothing at all can be concluded about the y component. MCQ6 ~Two satellites are orbiting around Mars with the same orbital radius. Satellite 2 has twice the mass of satellite 1. The centripetal acceleration of satellite 2 has: (a) twice the magnitude of the centripetal acceleration of satellite 1 ‘/ the same magnitude as the centripetal acceleration of satellite 1 (c) half the magnitude of the centripetal acceleration of satellite 1 (d) four times the magnitude of the centripetal acceleration of satellite 1 ‘ MCQ7- Two vectors are given as follows: A = -2i-7j + 2k B = -5i -2j -3k The angle between vectors A and B ,in degree , is close to: / (as) -' at... eat—sneaker; 63) fl 7: [0+iLl”£” Wale (c) 90° ’ v (2)1 o 4.qu (. 3) ’f’ 0 (d) 113 (e)130° / i X @{figé’i’ MCQ8— An elevator is moving upward with a speed of 11 m/s. Three seconds later, the elevator is still moving upward, but its speed has been reduced to 5.0 m/s. What is the average acceleration of f\ the elevator during the 3.0 s interval? N 5 A (a) 2.0 m/sz, upward U 1 i l 3 U 7’ :1 /\ (1:)s3/2 d L .2 a) " [Id ,223 is..-u.__ at)” (c) 2.7 m/sz, downward 0L ’k’ ’l; I “ ’3 1.“ [@20 m/sz, downward (e) 5.3 m/sz, downward MCQ9 -A car traveling along a road begins accelerating with a constant acceleration of 1.5 [Tl/52 in the direction of motion. After traveling 392 m at this acceleration, its speed is 35 m/s. Determine the speed of the car when it began accelerating. (a) 1.5 m/s U L: 0.3+?“ D74 (b) 34 31/5 I” 3T2; (c 2.3 m/s 3°52: Usz‘l'ga 3)( M7.0m/s 09/: m 2 Cline/S (e) 49m/s Part II -— Essay Questions Answer only three questions Question 1 (7points) Part (A) A person walks 0.50 km due east, 0 .75km due south, and 2.15kmin a directlon 35. 0" north of west. The time required for this trip is 2. 50h. . (a) Determine the magnitude and direction (relative to due west) of the person' s (i) displacement and (ii) average velocity (b) What is his average speed for the entire trip? ._.-7 SLA :0 A A ~>:_,o’+53 A A Part B The position of a particle as a function of time is given by 1': (3t2 -2t)i — t j In. Find: (a) its velocity at t =25; (b) its acceleration at 4s; (c) its average acceleration between t=ls and t=3s 3 fs 0+) Question 2 (7points) A ball is thrown vertically upward with a speed of 25.0n1/s. (a) How high does it rise? (b) How long does it take to reach its highest point ‘2 (c) How long does the ball take to hit the ground after it reaches its highest point? ((1) What is its velocity when it returnsto the level from it which is started ‘2 (e) What is the object’s final acceleration just before hitting the ground? V)5:o:1§“3qfi¢§tw9<:?: 3" -a 92:53 2% ‘i: zS”(’}.§7- Jifafléu) : 3-ng c, ["5 Ila—.1544) Question 3 (7points) A golf ball in the figure below leaves the position Q with a velocity of 40 m/s at 65°. If it lands on a position P located 10 In higher than the position Q, (a) what was the time of flight? (1)) what was the horizontal distances to the position Q? t (c) what is the speed of ball just before it hits the ground at the position P? (d) What was the ball's maximum height? git ni210 1—, EGLS‘JC Ame"; (54:? ttflt’a—gw T c 3% $1” $60qu let‘l 09,845C0n 1900—7 W19 q“. H 3 CW wer 4w“) ‘f we” 1:11 COQK— SB ‘IZ‘JKJV "k :- "7-~\\ S D: x(?—\\):Ho°\x’7H o m-umm “/5 3m o:C”+n)=U°v gen) 2-53"t A w\: baa-Uta :51H6 ”7/5. U190- "' Upg- (SAYM; fwd-4 -2—D—j—Z fl:3'}5 3 M2. (DD/’6‘ ngwzeaméq)459.3953 :6?M« Q9)? ~. L0)” (QM—M. Mal/Sm: Question 4 (7p0ints) Part A A 2. 0 kg ball tied to a string fixed to the ceiling is pulled to one side by a force F (see Fig below ) Just before the ball IS released and allowed to swing back and forth, (a) How large 15 the force F holding the ball 1n position? (b) What IS the tension in the string? Q Ts‘m'bo :1 m a 2 T563930 :- F ANA-L fl[email protected] T111030 <————-w~—>1 is: __ {1,530 ;7 F: CF39? M's W8:[\31N W _ 3:: 301. (A N ‘5” 0 ”Ir: Sinai Part B Two forces, F1 and F2 , act on the 5. 0kg block shown 1n the figure below The magnitudes of the forces are F1: 45 ON, and F2: 25.0 N. (a) What is the horizontal acceleration (magnitude and direction) of the block? i: c 55 (b) What is the normal force exerted on the block? ; N S m Em35~gz = max (Li‘SMBE-D‘Q‘S) S S?— “5 N: maffilé‘fig “‘03:”;51 (SO/tr 54435 93.9, N QR: Wk” Equation Sheet-Mid Term Test v = V0 + at , v2 3 V02 + 2a(x—xo) , X—X0=V0t+1/2at2 , X—Xo= 1/2(v0-l~v)t , For free-fall a=-g andXEy, g=9.8 m/SZ, Proiectile motion y : (tarlo.o)x--——2g—2—x2 2v0 cos (10 h P vozsinzoo R _ vo2sin 2010 2g g For circular motion vz 432R lel arad = mk— arad T2 Newton’s law of motion 2 F = Fnet = ma, f = um, Weight: mg , -bi\/b2 —-4ac 2a root = ...
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