Answer Key
Part A – 1: 23,
2: A,
3: D,
4: A
4 pts each.
Subtract 2 points from #2 for each incorrect additional answer, minimum of 0 points.
5: A,
6: A,
7: C,
8: B,
9: C,
10: B,
11: A,
12: C
2 pts each.
For #11, 1 point partial credit if it agrees with #6 but is wrong.
(Don't miss please.)
B1 20 Points
The key to this problem is the elastic collision.
The easiest method to solve the problem
is to use equations 45a to find V
2i
and 45b or 44x to find V
2f
.
0
.
1
v
)
v
)(
5
.
1
(
)
4
)(
5
.
0
(
5
.
3
v
m
m
m
2
v
m
m
m
m
v
i
,
2
i
,
2
i
,
2
2
1
2
i
,
1
2
1
2
1
f
,
1

=
→
+

=

→
+
+
+

=
m/s
5
.
1
)
0
.
1
)(
5
.
0
(
)
4
)(
5
.
0
(
v
m
m
m
m
v
m
m
m
2
v
i
,
2
2
1
1
2
i
,
1
2
1
1
f
,
2
+
=

+
=
+

+
+
=
m/s
Looking For
using conservation of momentum or equation 45.
using KE before = KE after or equation 45.
constant V
2
before and after collision.
straight line V
2
during collision.
.
correct value of V
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 Spring '08
 Grassers
 Physics, Force, Kinetic Energy, Momentum, KE, correct value

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